Answer:
-1/4
Step-by-step explanation:
-3/8 - 7/8= 4/8=1/2
Starting from the fundamental trigonometric equation, we have

Since
, we know that the angle lies in the third quadrant, where both sine and cosine are negative. So, in this specific case, we have

Plugging the numbers, we have

Now, just recall that

to deduce

Answer:
Huh
Step-by-step explanation:
Answer:
Slope = 1
Step-by-step explanation:
(x1, y1) = (-5, -3)
(x2, y2) = (-1, 1)
(y2 - y1) / (x2 - x1) = (1 - -3) / (-1 - -5) = 4 / 4 = 1
Slope = 1
Answer:
<em>B)</em><em> 8.9 lbs
</em>
<em>C)</em><em> 9.5 lbs
</em>
<em>D)</em><em> 9.8 lbs
</em>
<em>E)</em><em> 10.4 lbs</em>
Step-by-step explanation:
From the graph, 9.5 is the mean of the sample and 0.5 is the standard deviation of the sample.
As we have to find the weights that lie within the 2 standard deviations of the mean i.e


Among the given weights only 8.9 lbs, 9.5 lbs, 9.8 lbs, 10.4 lbs will lie within 2 standard deviations of the mean.