Answer:
123,456.789
Step-by-step explanation:
The ten thousandth place is less than 5.
Using the z-distribution, it is found that the lower bound of the 99% confidence interval is given by:
d. 68.39%.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 99% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 2.575.
The sample size and estimate are given by:

Hence, the lower bound is given by:

Hence the lower bound is of 68.39%, which means that option D is correct.
More can be learned about the z-distribution at brainly.com/question/25890103
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Answer:
the answer to the first one would be: 4/3
the second problem's answer: 20/36, which can be reduced to 5/9