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3 years ago

5

JOSIE HAS 43 ANIMAL BOOKS AND 29 ART BOOKS . SHE PUTS ALL THE BOOKS ON 8 SHELVES . SHE PUTS THE SAME NUMBER OF BOOKS ON EACH SHE

LF HAW MANY BOOKS DOES JOSIE PUT ON EACH SHELVES

2 answers:

Stels [109]3 years ago

8 0

Answer: 9

Step-by-step explanation:

43+29=72

72/8=9

zepelin [54]3 years ago

7 0

Answer:

9 books on each shelf

Step-by-step explanation:

43 + 29 = 72 books total

72/8 = 9 books per shelf

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If RX=4 and XS=9, then XT=<br> And how do you get it?

konstantin123 [22]

Answer:

XT=6 units

Step-by-step explanation:

The picture of the question is the attached figure

step 1

In the right triangle RST

Applying the Pythagorean theorem

$RS^2=RT^2+TS^2$

we have

$RS=RX+XS=4+9=13\ units$ ---> by segment addition postulate

substitute

$RT^2+TS^2=169$ ----> equation A

step 2

In the right triangle RTX

Applying the Pythagorean theorem

$RT^2=RX^2+XT^2$

we have

$RX=4\ units$

substitute

$RT^2=4^2+XT^2$

$RT^2=16+XT^2$

$XT^2=RT^2-16$ ----> equation B

step 3

In the right triangle XTS

Applying the Pythagorean theorem

$TS^2=XS^2+XT^2$

we have

$XS=9\ units$

substitute

$TS^2=9^2+XT^2$

$TS^2=81+XT^2$

$XT^2=TS^2-81$ ----> equation C

step 4

equate equation B and equation C

$TS^2-81=RT^2-16$

$TS^2-RT^2=81-16$

$TS^2-RT^2=65$ ----> equation D

step 5

Solve the system

$RT^2+TS^2=169$ ----> equation A

$TS^2-RT^2=65$ ----> equation D

Solve by elimination

Adds equation A and equation D

$RT^2+TS^2=169\\TS^2-RT^2=65\\---------\\TS^2+TS^2=169+65\\2TS^2=234\\TS^2=117$

Find the value of RT^2

$RT^2+117=169\\RT^2=52$

step 6

Find the value of XT

equation C

$XT^2=117-81\\XT^2=36\\XT=6\ units$

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d = 21

an = 12 + (2-1)21
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