Alex drew the triangles shown. What correctly describes the triangles

Mathematics

1 answer:

KATRIN_1 [288]3 years ago

6 0

Answer:

Congruent triangles

Step-by-step explanation:

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3/4 + 3/9 how do i do this

Artist 52 [7]

Answer:

13/12

Step-by-step explanation:

Well, you can't add it yet because the denominators don't match. We can't subtract two fractions with different denominators. So you need to get a common denominator. To do this, you'll multiply the denominators times each other... but the numerators have to change as well. So, multiply 3 by 8, and get 24. Since 4 is evenly divided by 8, we can multiply just one term to get a common denominator. Multiply 3 by 2, and get 6, then we multiply 4 by 2 and get 8. Since our denominators match, we can add the numerators. So now your answer should be 9/8. Well guess what... IT IS THE ANSWER! You can't reduce it anymore so 9/8 is your answer! Hope this helped!

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3 years ago

Name this polynomial by its degree: 3x² + 5x-3

rodikova [14]

Answer:

quadratic

Step-by-step explanation:

because it has degree 2

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3 years ago

The area of sector A08 is 48x and m<AOB = 270º. Find the radius of circle O.

Softa [21]

Answer:

Step-by-step explanation:

The first one gives us everything we need except the radius, which is easy enough to solve for if you're careful with your algebra. The area of a sector of a circle is given as:

$A_s=\frac{\theta}{360}*\pi r^2$ where θ is the measure of the central angle of the circle. For us, that fills in as follows:

$48\pi=\frac{270}{360}*\pi r^2$ and manipulate it as follows:

$r^2=\frac{(360)(48\pi)}{270\pi}$ the π's cancel out, leaving us with simple multiplication and division to get

r = 8. Now for the next one, which is a bit more involved.

In order to find the area of the shaded part, we need to find the area of the right triangle there and subtract it from the area of the sector of the circle. First the area of the sector, which is given as:

$A_s=\frac{\theta}{360}*\pi r^2$ where θ again is the measure of the central angle of the circle, 90°:

$A_s=\frac{90}{360}(3.1415)(10)^2$ which simplifies a bit to

$A_s=\frac{1}{4}(3.1415)(100)$ , giving us an area of

$A_s=78.5375m^2$ . Now onto the area of the triangle.

Since this triangle is inscribed in the circle and the circle's radius is 10, tha also gives us both the height and the base measures of the triangle. The area then is:

$A_t=\frac{1}{2}(10)(10)$ which is