Find the interest rate for $9000 deposit accumulating to $9889, compounded annually for 5 years.

Anton [14]

I think the correct answer your looking for is D) 9

5 0

3 years ago

Evaluate the following integral in cylindrical coordinates triple integral 1/(1+x^2+y^2) dzdxdy z=0..2 y=0..square root(1-x^2) x

sertanlavr [38]

In cylindrical coordinates, we take

$x=r\cos\theta$

$y=r\sin\theta$

$z=z$

so that $\mathrm dx\,\mathrm dy\,\mathrm dz=r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz$ .

We have

$1+x^2+y^2=1+r^2$

and the integral is

$\displaystyle\int_0^2\int_0^\pi\int_0^1\frac r{1+r^2}\,\mathrm dr\,\mathrm d\theta\,\mathrm dz=\frac{\ln2}2\int_0^2\int_0^\pi\mathrm d\theta\,\mathrm dz=\boxed{\pi\ln2}$

8 0

3 years ago

(01.04)

Neko [114]

33 represents how many people that were seen on the street at the time when writing the equation

3 0

3 years ago

A recent study reported that high school students spend an average of 94 minutes per day texting. Jenna claims that the average

larisa [96]

Answer:

We have sufficient evidence to support the claim that the average for the students at Jenna's large high school is greater than 94 minutes.

Step-by-step explanation:

Jenna claims that the average time of texting at her larger high school is greater than 94 minutes per day.

From here we can see that we have to perform a hypothesis test about a sample mean. The null and alternate hypothesis will be:

Null Hypothesis: $\mu \leq 94$

Alternate Hypothesis: $\mu > 94$

Jenna collected data from a sample of 32 students. So, sample size will be:

Sample Size = n = 32

Sample Mean = x = 96.5

Sample Standard Deviation = s = 6.3

We have to perform a hypothesis test, to test Jenna's claim. Since, the value of Population Standard Deviation is unknown and the value of Sample Standard Deviation is known, we will use One Sample t-test in this case.

The formula to calculate the test statistic is:

$t=\frac{x-\mu}{\frac{s}{\sqrt{n}}}$

Using the values, we get:

$t=\frac{96.5-94}{\frac{6.3}{\sqrt{32} } }=2.245$

The degrees of freedom will be:

df = n - 1 = 32 - 1 = 31

We have to convert the t-score 2.245 with 31 degrees of freedom to its equivalent p-value. From t-table this value comes out to be:

p-value = 0.0160

The significance level is:

$\alpha =0.05$

Since, the p-value is lesser than the level of significance, we reject the Null Hypothesis.

Conclusion:

We have sufficient evidence to support the claim that the average for the students at Jenna's large high school is greater than 94 minutes.

3 0

4 years ago

maya purchased a prepaid phone card for $25.00. Calls cost 25 cents a minute using this card. the credit, C (in dollars), left o

Kay [80]

Answer:

$20 of credit left on the card

Step-by-step explanation:

If we say that the prepaid phone card has 25 minutes on it since Maya paid 25 dollars for it. We can multiply 25 times 4 which equals 1 dollar per 4 minutes. Then, we can divide 20 by 4 to get 5 which means that she used 5 dollars of call time. We can now subtract 25-5 and we get 20. This tells us that there is 20 dollars left on the card.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

4 0

3 years ago

Find the interest rate for ​$9000 deposit accumulating to ​$9889​, compounded annually for 5 years.

Find the interest rate for $9000 deposit accumulating to $9889, compounded annually for 5 years.