Hello,
A(x)=x²-x-72 (m²)
L=(x+8) (cm)= (x+8)/100 (m)
We suppose here x≠-8
(in reality x²-x-72>0 ==>x<-8 or x>9
but x+8>0 ==> x>-8
then
only x>9 are solutions)
W=A(x)/ ((x+8)/100 )=100*(x²-x-72)/(x+8)= 100*(x-9)(x+8)/(x+8)=100*(x-9)
The answer is true because the X (to the right) values does not repeat itself
Given:
The given sets are:
Set a : 200, 104, 100, 160.
Set b: 270, 400, 483, 300, x.
Mean of set a: mean of set b= 3:8
To find:
The value of x.
Solution:
Formula for mean:
The mean of set of a is:
The mean of set of b is:
It is given that,
Mean of set a: mean of set b= 3:8
Isolate the variable x.
Divide both sides by 3.
Therefore, the value of x is 427.
Answer:
yes I do
Step-by-step explanation:
can you help me with my question In the extended simile of the underlined passage from Paragraph 15 of "A Wagner Matinee," the narrator makes an observation about the soul that aring rokol been A. it is like a strange moss on a dusty shelf that, with excruciating suffering, can wither and die y for I the be B though after excruciating suffering it may seem to wither, the soul never dies, C. excruciating, interminable suffering that goes on for half a century can kill the soul.
Answer:
624.5 feet
Step-by-step explanation:
Calculation to determine how many feet from the boat is the parasailor
Based on the information given we would make use of Pythagorean theorem to determine how many feet from the boat is the parasailor using this formula
a²+b²=c²
First step is to plug in the formula by substituting the given value
500²+b²=800²
Second step is to evaluate the exponent
250,000+b²=640,000
Third step is to substract 250,000 from both side and simplify
250,000+b²-250,000=640,000-250,000
b²=390,000
Now let determine how many feet from the boat is the parasailor
Parasailor feet=√b²
Parasailor feet=√390,000
Parasailor feet=b=624.49
Parasailor feet=b=624.5 feet (Approximately)
Therefore how many feet from the boat is the parasailor will be 624.5 feet
