Firstly, let's make an equation. We know that when y is 15, x is 3. Or, in other words, y is 5 times what x is. Therefore we can use the equation, y = 5x.

Now, just plug x into the equation.

y = 5(10)

y = 50

5 0

3 years ago

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5x^(-2)-17x^(-1)+6<br> i’m so confused pls help<br> will give brainliest

laila [671]

It's a quadratic equation in disguise. If you let $y=x^{-1}$ , then $y^2=x^{-2}$ , and we can rewrite the equation as

$5y^2-17y+6=0$

Solve for $y$ however you like; we get $y=\dfrac25$ and $y=3$ .

But we want to solve for $x$ , so we have

$y=x^{-1}=\dfrac25\implies x=\dfrac52$

$y=x^{-1}=3\implies x=\dfrac13$

5 0

3 years ago

57.8 ÷ 81 (63 points and too lazy to solve the questions but help!)

Luba_88 [7]

0.71358024691

If you are rounding then the answer would be 0.71

4 0

3 years ago

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