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3 years ago

Find the equation in slope-intercept form (10,4) that is perpendicular to y=5x-3

Mathematics

1 answer:

TEA [102]3 years ago

7 0

Perpendicular equation: y=-1/5x + 6

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Can 4,9, 15 represent the lengths of the sides of a triangle?

Gwar [14]

Answer:

Step-by-step explanation:

4,4,5 and 12,7,7 are isosceles triangles because they have two equal sides . 15,15,15 is an equilateral triangle -it has three equal sides

4 0

3 years ago

Read 2 more answers

What is the surface area plz help me !!

Masteriza [31]

Answer:

I hope this right

Step-by-step explanation:

16 in for the suface area so sorry if wrong

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2 years ago

This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex

harina [27]

$L(x,y,z,\lambda)=8x+8y+4z+\lambda(4x^2+4y^2+4z^2-36)$

$L_x=8+8\lambda x=0\implies 1+\lambda x=0$
$L_y=8+8\lambda y=0\implies 1+\lambda y=0$
$L_z=4+8\lambda z=0\implies 1+2\lambda z=0$
$L_\lambda=4x^2+4y^2+4z^2-36=0\implies x^2+y^2+z^2=9$

$yL_x=y+\lambda xy=0$
$xL_y=x+\lambda xy=0$
$\implies yL_x-xL_y=y-x=0\implies y=x$

$2zL_x=2z+2\lambda xz=0$
$xL_z=x+2\lambda xz=0$
$\implies 2zL_x-xL_z=2z-x=0\implies x=2z$

$2zL_y=2z+2\lambda yz=0$
$yL_z=y+2\lambda yz=0$
$\implies 2zL_y-yL_z=2z-y=0\implies y=2z$

$x=y=2z\implies x^2+y^2+z^2=9\iff 4z^2+4z^2+z^2=9z^2=9\implies z=\pm1$

$z=\pm1\implies y=x=\pm2$

So we have two critical points, (2, 2, 1) and (-2, -2, -1), which respectively give a max of 36 and a min of -36.

5 0

3 years ago

I need Help with 9??

andreyandreev [35.5K]

Sometimes it helps to draw it...so u can see

7 7
J_______K_________L
|__________________|
4x - 2

since K is the midpoint, it splits the segment in 2 equal parts
JK + KL = JL
7 + 7 = 4x - 2
14 = 4x - 2
14 + 2 = 4x
16 = 4x
16/4 = x
4 = x <====

KL = 7 <===
JL = 4x - 2....4(4) - 2.....16 - 2 = 14 <==

7 0

3 years ago

A recipe calls for 1 part beans to 1½ parts rice. if 1½ parts of beans are used, how much rice should be used?

riadik2000 [5.3K]

$1 \text{ part beans} \longrightarrow 1\dfrac{1}{2} \text{ parts rice}$

$1 \dfrac{1}{2} \text{ part beans} \longrightarrow 1\dfrac{1}{2} \times 1 \dfrac{1}{2} \text{ parts rice}$

$1 \dfrac{1}{2} \text{ part beans} \longrightarrow \dfrac{3}{2} \times \dfrac{3}{2} \text{ parts rice}$

$1 \dfrac{1}{2} \text{ part beans} \longrightarrow \dfrac{9}{4} \text{ parts rice}$

$1 \dfrac{1}{2} \text{ part beans} \longrightarrow 2\dfrac{1}{4} \text{ parts rice}$

8 0

3 years ago