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amid [387]
2 years ago
5

.Solve the following equations, leaving your answer as a fraction where appropriate: 10(2x + 12) = -7(x + 12) ​

Mathematics
1 answer:
Yanka [14]2 years ago
8 0
The answer is going to be 68/9 and the fraction is negative.
hope this help!
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0.75+0.25t

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The length of two sides of a triangle are 10, 15 find the range of possible lengths for the third side
Zepler [3.9K]

Answer:

Range for third side is  

( 5 , 25 )  cm.

Step-by-step explanation:

As two sides of triangle are  10  and  15 ,

the third side would have to be less than the sum of other two sides i.e. less than  25  cm.

On the other hand if it is smaller one than this side plus side of length  10

should be greater than  15  and therefore

this side is greater than  15 − 10 = 5  cm.

Hence range is  

( 5 , 25 )

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Mark brainliest

5 0
2 years ago
Can you help me please​
kotegsom [21]

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3

Step-by-step explanation:

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Find the values of x and y. Pls helpI’m helpless at math
Svetradugi [14.3K]

Answer:

  • x = 1
  • y=\frac{\sqrt{3}}{2}  

Step-by-step explanation:

From the given right-angle triangle

The angle = ∠60°

  • The adjacent to the angle ∠60° is 1/2.
  • The opposite to the angle ∠60° is y.

The hypotenuse = x

<u>Determining the value of x:</u>

Using the trigonometric ratio

cos 60° = adjacent / hypotenuse

substituting adjacent = 1/2 and hypotenuse = x

cos\:60^{\circ }=\:\:\frac{\frac{1}{2}}{x}

\cos \left(60^{\circ \:}\right)=\frac{1}{2x}

\frac{1}{2}=\frac{1}{2x}          ∵ cos (60°) = 1/2

2x=2

Dividing both sides by 2

\frac{2x}{2}=\frac{2}{2}

Simplify

x=1

Thus, the value of hypotenuse x is:

x = 1

<u>Determining the value of y:</u>

Using the trigonometric ratio

sin 60° = opposite / hypotenuse

As we have already determined the value of hypotenuse x = 1

substituting opposite = y and hypotenuse = 1

sin 60° = y/1

y = 1 × sin 60°

y=\frac{\sqrt{3}}{2}       ∵  \sin \left(60^{\circ \:}\right)=\frac{\sqrt{3}}{2}

Therefore, the value of y is:

y=\frac{\sqrt{3}}{2}      

Summary:

  • x = 1
  • y=\frac{\sqrt{3}}{2}    
5 0
3 years ago
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