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serious [3.7K]
3 years ago
12

Prove that the value of expression 97+312 is divisible by 90.

Mathematics
1 answer:
Mrac [35]3 years ago
7 0

Answer:

97 + 312 = 409

409 is not divisible by 90.

There must be a mistake in the question.

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Given that 7 x − 2 y = 35 Find y when x = − 9
Sergio [31]

so x = minus 9

then

7 × (-9) - 2y = 35

-63 - 2y = 35

-2y = 35 plus 63

-2y = 98

- y = 49

y = -49

3 0
3 years ago
Read 2 more answers
[(-6) + 5] ÷ [(-2) + 1]
Ira Lisetskai [31]
Answer:

Answer is 1

Explanation:

(-6 + 5) / (-2 + 1)

-1 / -1

1
3 0
3 years ago
Read 2 more answers
A certain virus infects one in every 300 people. A test used to detect the virus in a person is positive 90​% of the time when t
garik1379 [7]

Answer:

a)  P[A/B] = 0,019     or     P[A/B] = 1,9 %

b)  P[A- /B-] = 0,9996       or    P[A- /B-] = 99,96 %

Step-by-step explanation:

Bayes Theorem :

P[A/B]  =  P(A) * P[B/A] / P(B)

The branches of events are as follows

Condition 1        real infection     1/300        and     not infection  299/300

Then

1.-    1/300      299/300

When the test is done   (virus present)  0,9 (+)    0,15 (-)

2.-   299/300

When the test is done  ( no virus )   0,15  (+)     0,85 (-)

Then:

P(A) = event person infected          P(B)  =  person test positive

a) P[A/B]  = P(A) * P[B/A] / P(B)

where   P(A)  = 1/300  =   0,0033   P[B/A] = 0,9    

Then P(A) * P[B/A] =  0,0033*0,9  =  0,00297

P(B)   is    ( 1/300 )*0,9  +  (299/300)*0,15

P(B) = 0,0033*0,9 + 0,9966*0,15    ⇒  P(B) = 0,1524

Finally

P[A/B] =  0,00297 /0,1524

P[A/B] = 0,019     or     P[A/B] = 1,9 %

b) Following sames steps:

P[A- /B-] = (299/300) * 0,85  / (299/300) * 0,85 + (1/300 * 0,1)

P[A- /B-] = 0,8471 /0,8474

P[A- /B-] = 0,9996       or    P[A- /B-] = 99,96 %

6 0
3 years ago
when atc has not imposed any climb or descent restrictions and aircraft are within 1,000 feet of assigned altitude, pilots shoul
ziro4ka [17]

In the absence of ATC restriction on climb or descent, and aircraft are within 1,000 feet of assigned altitude. pilots should attempt to both climb and descend at a rate of between 500 fpm and 15000 fpm. (Option A)

An Air Traffic Controller (ATC) clearance refers to an authorization by ATC for the purpose of preventing known aircraft collision. The rate of climb or descend expected by ATV is when an aircraft is within 1000 feet of assigned altitude, descend, or climb at an optimum rate consistent with the operating characteristics of the aircraft to 1,000 feet above or below the assigned altitude, and then attempt to descend or climb at a rate of between 500 and 1,500 fpm until the assigned altitude is reached.

Learn more about Air Traffic Controller (ATC):

brainly.com/question/5018782

#SPJ4

7 0
1 year ago
Pleasee help !!!!!!!
VLD [36.1K]

Answer: x = -1 and x= -5

Step-by-step explanation:

Try plugging in the solutions for x (remember that whatever number comes out of the absolute value bars is ALWAYS POSITIVE)

4 0
3 years ago
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