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3 years ago

Fill in the blank.

Mathematics

1 answer:

gavmur [86]3 years ago

6 0

Answer:

297 cubic centimeters

Step-by-step explanation:

volume is LWH

11*9*3 = 297

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3x+5(2+x)=4x-7 help me out here?

Oksi-84 [34.3K]

Answer:

x = -17/4

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Distributive Property

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

3x + 5(2 + x) = 4x - 7

Step 2: Solve for x

[Distributive Property] Distribute 5: 3x + 10 + 5x = 4x - 7
[Addition] Combine like terms: 8x + 10 = 4x - 7
[Subtraction Property of Equality] Subtract 4x on both sides: 4x + 10 = -7
[Subtraction Property of Equality] Subtract 10 on both sides: 4x = -17
[Division Property of Equality] Divide 4 on both sides: x = -17/4

6 0

2 years ago

Read 2 more answers

What’s the piremeter of a polygon

Burka [1]

Answer:

the length of all sides added together

6 0

2 years ago

Which fraction is greater than 3 + 1/2 - 55/8 or 7/8

Mila [183]

7/8 is ur answer because
it can be cut into smaller parts

8 0

2 years ago

Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137

Nata [24]

Answer:

Camera 2nd has to cover the maximum angle, i.e. $78.70^\circ$ .

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle $\triangle ABC$ with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles $\angle A, \angle B, \angle C$

As per Law of cosine:

$cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}$

Putting the values of a,b and c to find out angles $\angle A, \angle B, \angle C$ .

$cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ$

$cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ$

$cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ$