LN = 120 and a = 10
<u>Step-by-step explanation:</u>
If we need to find the variable a as, LN is the line and M is the mid point between L and N. So LN = LM + MN
LM = 4a = 40
a =
= 10
MN = 8a = 8×10 = 80
So LN = LM + MN
LN = 40 + 80 = 120
We have that
2sin²<span>x - sinx - 3 = 0
</span>
Let
A------> sin x
so
2A²-A-3=0
using a graph tool-----> to resolve the second order equation
see the attached figure
the solutions are
A=-1
A=1.5------> is not solution because sin x <span>can not be 1.5
the solution is
A=-1
therefore
sin x=-1
x=arc sin(-1)=-90</span>°
the answer is
sin x=-1x=-90° or 270°
Answer:
Step-by-step explanation:
The first thing you ought to do is find out what you are trying to get. Desmos is an ideal program to do that if you don't have a graphing calculator. Just search for Desmos. It is pretty obvious once you get there. I've enclosed the graph to show you what it looks like.
Notice what happens around 5. The graph splits because effectively, you are dividing by 0 when you put 5 into the denominator. The question arises why doesn't the same thing happen at 0. It should: There is a discontinuity but it is very tiny. So the domain numbers that you should graph are
-1 0™ 1 2 3 4 4.5 4.8 5.3 5.4 6 7
™I wouldn't make 0 a part of this domain. But you can indicate with a dot where the graph goes.
I haven't filled in the range numbers. That's your job. All you have to do is fill in the table with points. Or you can put them on the graph that I have enclosed just to see where they points belong.
A graph is not to convey accuracy. It is to show the shape of function in question.
Answer: this is only for the first question i think its the second one and the 3rd one i think
As diagonals are not perpendicular, it cannot be a square or rhombus (latter does not have congruent diagonals). Hence, quadrilateral is a rectangle.