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dem82 [27]
4 years ago
12

( simplify the following polynomials. All final answers must be in standard form )

Mathematics
1 answer:
Mila [183]4 years ago
3 0
\frac{6x^3-15x^2-3x}{3x} = 2 x^4 - 5 x^3 -x^2
\frac{7x^3-4x^2-2x}{x^2} =  7 x -  \frac{2}{x} -4
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Step-by-step explanation:

The last three are irrational but I'm not sure about the first four.

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Prove that (AxB).(BxC)+(BxC).(AxD)+(CxA).(BxD)=0
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Which equation is represented by the table?
MatroZZZ [7]

Answer:

y=-|x-3|-3

Step-by-step explanation:

The table shows values of y for different values of x.

Let us test each equation with the values given in the table.

Equation 1: y=|x+3|-3

For x = 1, we get,

y=|x+3|-3=|1+3|-3=|4|-3=4-3=1

So, we got 1 for y. But as per table, value of y should be -5.

So, equation 1 is incorrect.

Equation 2: y=-|x-3|-3

For x = 1, we get,

y=-|x-3|-3=-|1-3|-3=-|-2|-3=-(2)-3=-5

So, we got -5 for y. It matches with the value of table.

Let us check for another value of x in order to confirm.

For x =2, we get,

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So, we got -4 for y. It matches with the value of table.

So, equation 2 is the correct answer.

We can be completely sure by checking the remaining equations too.

Equation 3: y=|x-3|-3

For x = 1, we get,

y=|x-3|-3=|1-3|-3=|-2|-3=2-3=-1

So, we got -1 for y. But as per table, value of y should be -5.

So, equation 3 is incorrect.

Equation 4: y=-|x+3|-3

For x = 1, we get,

y=-|x+3|-3=-|1+3|-3=-|4|-3=-4-3=-7

So, we got -7 for y. But as per table, value of y should be -5.

So, equation 4 is incorrect.

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3 years ago
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