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dem82 [27]
3 years ago
12

( simplify the following polynomials. All final answers must be in standard form )

Mathematics
1 answer:
Mila [183]3 years ago
3 0
\frac{6x^3-15x^2-3x}{3x} = 2 x^4 - 5 x^3 -x^2
\frac{7x^3-4x^2-2x}{x^2} =  7 x -  \frac{2}{x} -4
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Someone help me please and thank you!! ASAP :(
pantera1 [17]
<h3>Answer: Choice D) </h3>

Work Shown:

(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\

We must require that x \ne -12 and x \ne 3 to avoid having 0 in the denominator. This is why choice D is the answer.

3 0
3 years ago
Kerry's car is valued at $11,250 if the property tax rate is 1.5% how much tax does she owe​
eimsori [14]

Answer:

168.5

Step-by-step explanation:

8 0
3 years ago
Which point on the graph shows the amount of water in the bucket after 1 second? Hint: Type your answer in the form (x coordinat
Taya2010 [7]

Answer:

\displaystyle \left(1,\frac{5}{12}\right)

Step-by-step explanation:

<u>Graphs</u>

The graph shows the amount of water in gallons as a function of time in seconds.

We are required to find the amount of water in the bucked after 1 second. Since the graph does not show an exact location for t=1, we must find the equation of the line.

Two points are clear on the graph: (0,0) (12,5). This gives us the necessary information to find the equation of the line, which has the form:

w=mt+b

Where w is the amount of water in the bucket, t is the time, and m and b are two constants to be determined.

Using the point (0,0):

0=m(0)+b

It follows that b=0

The equation now takes the form:

w=mt

Using the point (12,5):

5=m(12)

We find m:

\displaystyle m=\frac{5}{12}

The final equation is:

\displaystyle w=\frac{5}{12}\cdot t

Substituting t=1:

\displaystyle w(1)=\frac{5}{12}\cdot (1)=\frac{5}{12}

The bucket has 5/12 gallons of water at t=1 second. Expressing the answer as an ordered pair:

\boxed{\displaystyle \left(1,\frac{5}{12}\right)}

6 0
3 years ago
Alice weighs 20 dogs and 20 cats. The mean weight for the dogs is 32kg and the mean weight for cats is 4kg. The range in weight
azamat

With the mean and range, we can estimate the weights of the smallest and largest animals in each group.

For cats the interval is [ 3.75kg, 4.25kg] and for dogs is [9.5kg, 54.5kg]

<h3>Which conclusions can be made with the given information?</h3>

We know that the mean weight for cats is 4kg, and the range (difference between the largest value and smallest value) is 0.5kg.

  • From that, we can conclude with some confidence (but not exactly), that the largest cat weights 4kg + 0.5kg/2 = 4.25kg
  • And the smallest cat weights 4kg - 0.5kg/2 = 3.75kg

(Assuming a normal distribution).

Similar for the dogs, the mean weight is 32kg and the range is 45kg, then:

  • The largest dog weights 32kg + 45kg/2 = 54.5kg
  • The smallest dog weights 32kg - 45kg/2 = 9.5kg

(again, assuming a normal distribution).

If you want to learn more about means and ranges:

brainly.com/question/14532771

#SPJ1

3 0
2 years ago
What is the probability of rolling a number greater than 2 on one roll of a die and a 6 on a second roll of a die?
ch4aika [34]
Explanation:
There are
6
possible outcomes:
{
1
,
2
,
3
,
4
,
5
,
6
}

4
of these outcomes are greater than
2
: {3.4.5.6}#
So the probability of a roll greater than
2
is
4
out of
6

XXX
=
4
6
=

2/3



Mark brainliest please


Hope this helps you
Answer link
8 0
2 years ago
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