Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval:
(-15,-10).
<h3>What is the slope of the tangent line to a function f(x) at point x = x0?</h3>
It is given by the derivative at x = x0, that is:
.
In this problem, the function is:
Hence the derivative is:
For a slope of -1, we have that:
0.4x + 5 = -1
0.4x = -6
x = -15.
For a slope of 1, we have that:
0.4x + 5 = 1.
0.4x = -4
x = -10
Hence the interval is:
(-15,-10).
More can be learned about derivatives and tangent lines at brainly.com/question/8174665
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Answer:
22
Step-by-step explanation:
400/18=22.222222222
Round to 22
5 Hope I helped. Have a good day
Answer:
T=98W-115W+1840
Step-by-step explanation:
$98 per credit at Westside (W)
$115 per credit at Pinewood (P)
Expression 1 : 98W+115P=T
Expression 2 : W+P=16
Combined: if W=16-P
Total=98W+115(16-W)
T=98W-115W+1840
The correct answer is option B. i.e. the experimental probability is 3% greater than the theoretical probability<span>
The </span>theoretical Outcomes are: HH HT TH TT
Then, the probability of getting HH = 1/4 = 0.25 = 25%
Now, Experimental Outcomes : <span>HH=28 HT=22 TH=34 TT=16
Total number of outcomes = 28+22+34+16 = 100
</span>Then, the probability of getting HH = 28/100 = 0.28 = 28%
Thus, <span>the experimental probability is 3% greater than the theoretical probability</span>
