All categories

3 years ago

Suppose you have a normally distributed set of data pertaining to a standardized test. The mean

1 answer:

lina2011 [118]3 years ago

7 0

<span>The formula to find the z score in a normally distributed set of data is: z = (x - ÎĽ) / Ď With ÎĽ being the mean, Ď being the standard deviation, and x being the score. Substituting these values into the formula gives us z = (800 - 500) / 100 = 3 The z-score of the 800 point score is 3.</span>

You might be interested in

Simplify completely 12x^3-4x^2+8x/-2x<br> PLEASE HELP

Amiraneli [1.4K]

The answer is 12x^3-4×^2-4

4 0

3 years ago

Two number cubes are rolled.

Olegator [25]

Cubes have 6 numbers
3 odd, 3 even

probablity=desiredoutcome/totalpossibleoutcomes
there are 6 total desired outcomes (3 on each cube)
total possible, there are 6*6 or 36 total possible outcomes
so 6/36 or 1/6 chance

3 0

3 years ago

Read 2 more answers

Suppose that the duration of a particular type of criminal trial is known to be normally distributed with a mean of 22 days and

Alika [10]

Answer:

25.5 days

Step-by-step explanation:

Mean number of days (μ) = 22 days

Standard deviation (σ) = 6 days

Z-score for the 72nd percentile (according to tabulated values) = 0.583

The z-score for any number of days, X, is determined by:

$z=\frac{X-\mu}{\sigma}$

The value of X that is greater than 72% of the trial times is:

$0.583=\frac{X-22}{6}\\ X=25.5\ days$

Therefore, 72% of all of these types of trials are completed within 25.5 days.

6 0

3 years ago

Which classification best represents a triangle with side lengths 6 cm, 10 cm, and 12 cm?

DedPeter [7]

Answer:

obtuse because 62 + 102 < 122

3 0

2 years ago

Read 2 more answers

The focus of a parabola is located at (0,–2). The directrix of the parabola is represented by y = 2. Which equation represents t

Archy [21]

Answer:

$\boxed{x^2=-8y}$

Step-by-step explanation:

$(a,b)\ is \ the\ focus\\y=k\ is \ the\ directrice\\\\Formula\ to\ use:\ y=\dfrac{(x-a)^2}{2(b-k)} +\dfrac{b+k}{2} \\\\Here: \ a=0,\ b=-2, \ k=2\\\\y=\dfrac{(x-0)^2}{2(-2-2)} +\dfrac{-2+2}{2} \\\\so\ y=-\dfrac{x^2}{8} \\\\or\ x^2=-8y$

3 0

3 years ago