Suppose you have a normally distributed set of data pertaining to a standardized test. The mean

1 answer:

lina2011 [118]3 years ago

7 0

<span>The formula to find the z score in a normally distributed set of data is: z = (x - ÎĽ) / Ď With ÎĽ being the mean, Ď being the standard deviation, and x being the score. Substituting these values into the formula gives us z = (800 - 500) / 100 = 3 The z-score of the 800 point score is 3.</span>

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The equation we use to solve this is in the form
$A=p(1+\frac{r}{n})^{nt}$ ,
where A is the total amount in the account, p is the principal invested, r is the interest rate as a decimal, n is the number of times per year the interest is compounded, and t is the amount of time.

A in our problem is 14000.
p is unknown.
r is 6% = 6/100 = 0.06.
n is 2, since it is compounded semiannually.
t is 13.

$14000=p(1+\frac{0.06}{2})^{13*2}
\\
\\14000=p(1+0.03)^{26}
\\
\\14000=p(1.03)^{26}
\\
\\\text{Dividing both sides by }1.03^{26}\text{, we have}
\\
\\\frac{14000}{1.03^{26}}=\frac{p(1.03)^{26}}{1.03^{26}}
\\
\\6491.73\approx p$

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Answer:

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Step-by-step explanation:

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