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3 years ago

Hello there, help me ^_^

Mathematics

1 answer:

Dimas [21]3 years ago

8 0

Answer:

q1: $x^{3} -64$

q2: $6x^{3} -14x^{2} +19x-5$

Step-by-step explanation:

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A pie was cut into two equal pieces. Each of the pieces of pie was cut into halves again, and each of those smaller pieces was c

jarptica [38.1K]

Answer:

6 pieces, 6/8

Step-by-step explanation:

You have 8 pieces you take away 2 you get 6.

8-2=6

3 0

4 years ago

Read 2 more answers

I have the answer, 2-(3/x+2)

Marat540 [252]

Start with the answer format we want, and work your way toward forming a single fraction like so

$a + \frac{b}{x+2}\\\\a*1+\frac{b}{x+2}\\\\a*\frac{x+2}{x+2}+\frac{b}{x+2}\\\\\frac{a(x+2)}{x+2}+\frac{b}{x+2}\\\\\frac{a(x+2)+b}{x+2}\\\\\frac{ax+2a+b}{x+2}\\\\\frac{ax+(2a+b)}{x+2}\\\\$

Compare that last expression to (2x+1)/(x+2). Notice how the ax and 2x match up, so a = 2 must be the case.

Then we have 2a+b as the remaining portion in the numerator. Plugging in a = 2 leads to 2a+b = 2*2+b = 4+b. Set this equal to the +1 found in (2x+1)/(x+2) to have the terms match.

So, 4+b = 1 leads to b = -3

Therefore, a = 2 and b = -3

------------------------------------------------

An alternative route:

$\frac{2x+1}{x+2}\\\\\frac{2x+1+0}{x+2}\\\\\frac{2x+1+4-4}{x+2}\\\\\frac{(2x+4)+1-4}{x+2}\\\\\frac{2(x+2)-3}{x+2}\\\\\frac{2(x+2)}{x+2}+\frac{-3}{x+2}\\\\2-\frac{3}{x+2}\\\\$

I added and subtracted 4 in the third step so that I could form 2x+4, which then factors to 2(x+2). That way I could cancel out a pair of (x+2) terms toward the very end.

------------------------------------------------

Other alternative methods involve synthetic division or polynomial long division. They are slightly separate but related concepts.

3 0

3 years ago

Read 2 more answers

2c + 3a - 4c + 8<br><br> (The letters don't have any equals)

vodomira [7]

Answer:

3a -2c +8

You have to combine the same letters together, which is only 2c and -4c. Then you just write the rest of the equation.

6 0

3 years ago

Read 2 more answers

Which two values of x are roots

FrozenT [24]

The answer is C.

To solve these types of equations you first need to make sure that you equation is equal to 0. In this case all of the numbers are already on the same side so no work needs to be done there. Then we can get a, b and c values for the quadratic equation by looking at the coefficients.

a = 4 (number attached to x^2)
b = -6 (number attached to x)
c = 1 (number with no variable attached)

Now we can put this into the quadratic equation.

$\frac{-b +/- \sqrt{ b^{2} -4ac} }{2a}$

$\frac{6 +/- \sqrt{ -6^{2} -4(4)(1)} }{2(4)}$

$\frac{6 +/- \sqrt{20} }{8}$

6 0

4 years ago

What is the slope of the line shown below?AX10(3,7)1015(-2,-3)ch19A. -5OB. 5C. -2D. 2

Natali [406]

Given the graph from the question

We want to find the slope

Solution

From the graph, the major two points are already indicated

i.e.

$(-2,-3)\text{ and (3,7)}$

The formula to find the slope (m) is given as

$m=\frac{y_2-y_1}{x_2-x_1}$

Using the indicated coordinates

$\begin{gathered} x_1=-2 \\ y_1=-3 \\ x_2=3 \\ y_2=7 \end{gathered}$ $\begin{gathered} m=\frac{7-(-3)}{3-(-2)} \\ m=\frac{7+3}{3+2} \\ m=\frac{10}{5} \\ m=2 \end{gathered}$

Therefore, the slope is 2

Option D

6 0

1 year ago