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Reika [66]
3 years ago
7

a 5 inch tall bamboo shoot doubles in height every 3 days. if the equation, y=ab^x where x is the number of doubling periods, re

presents the height of the bamboo shot, what are the values of a and b?
Mathematics
1 answer:
Lemur [1.5K]3 years ago
3 0
X-doubling periods
Y-height of bamboo
Y=ab^x

1) make a table of values
X Y
1 5
2 10
3 20

2) write equations and substitute
5=ab^1 —> a=5/b^1 —> a=5/b
10=ab^2

Substitute into second equation

10=(5/b)*b^2
10=5b^2/b
10=5b
b=2

Substitute back in

b=2
10=a*2^2
10=4a
a=5/2

End equation:
Y=5/2*2^x


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The base of a rectangle lies on the x-axis, while the upper two vertices lie on the parabola y = 13 − x2. Suppose that the coord
Misha Larkins [42]

Answer:

Area of Rectangle = 26x - 2x^3

Step-by-step explanation:

Rectangle two vertices lie on x axis ; two vertices lie on parabola y = 13 - x^2.

Supposing coordinates of upper right vertex of rectangle are P = x , y

Due to parabola symmetry, width of rectangle is twice the distance  horizontal (X) axis distance between Y axis & point P.

Width of rectangle = 2x

Length of rectangle = y  ; y = 13 - x^2

Area of Rectangle = Length x Width

= 2x (y)

= 2x (13 - x^2)

= 26x - 2x^3

5 0
3 years ago
Triangle ABC is translated and then reflected to map triangle A"B"C" as shown.
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Answer:

Step-by-step explanation:

3 0
3 years ago
All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
3 years ago
Radius of x^2+y^2=25
SOVA2 [1]

Answer:

5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
For 50 Points!!!!!!!!!
dolphi86 [110]
Hello!

First you have to find what the temperature was at the 3 stages

It started at 87

Then went down 10

87 - 10 = 77

Then up 17

77 + 17 = 94

Then you take the difference from the current temperature from the lowest temperature

94 - 77 = 17

The answer is D

Hope this helps!
5 0
3 years ago
Read 2 more answers
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