Question is attached.Step by step explanation only!
2 answers:
Given :
- tan∅/1-cot∅ + cot∅/1-tan∅ = sin∅/cos∅ ÷ (1- cos∅/sin∅ ) + cos∅/sin∅ ÷ (1 - sin∅/cos∅)
To Do :-
Proof :-
<u>We </u><u>know</u><u> that</u><u> </u><u>,</u>
- sin∅/cos∅ = tan∅
- cos∅/sin∅ = cot∅
<u>On </u><u>using </u><u>above</u><u> </u><u>two </u><u>in </u><u>LHS</u><u> </u><u>,</u>
- LHS = tan∅/1-cot∅ + cot∅/1-tan∅
- LHS = tan∅/1-cot∅ + cot∅/1-tan∅ = sin∅/cos∅ ÷ (1- cos∅/sin∅ ) + cos∅/sin∅ ÷ (1 - sin∅/cos∅)
- LHS = RHS
Hence proved !
Answer:
See Below.
Step-by-step explanation:
We want to verify the equation:

Recall that tanθ = sinθ / cosθ. Likewise, cotθ = cosθ / sinθ. Then by substitution:

Hence verified.
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