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AleksandrR [38]
2 years ago
8

What is the correct maximum or minimum for the function f(x) = -|x-2| + 1

Mathematics
2 answers:
Usimov [2.4K]2 years ago
5 0

Answer:

1

Step-by-step explanation:

The graph is shifted up one unit

aniked [119]2 years ago
3 0

Answer:

  • f(max) = 1

Step-by-step explanation:

<u>Given function:</u>

  • f(x) = - |x - 2| + 1

<u>Since the value of the  |x - 2| can be zero or positive only, the graph has its maximum at x = 2:</u>

  • f(2) = 0 + 1 = 1
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Lowkey forgot how to do this so I’m stuck._.
expeople1 [14]

Answer:

113.04

Step-by-step explanation:

area is πr², so 3.14·6²·3.14 = 113.04

3 0
3 years ago
Read 2 more answers
I'm havingn trouble in math. What's 3/4 - 2/5 in fraction form?
snow_tiger [21]
\dfrac{3}{4}-\dfrac{2}{5}=\dfrac{15}{20}-\dfrac{8}{20}=\dfrac{7}{20}&#10;
6 0
3 years ago
Simpilify the expresssion 2+3i/4+3i
Eddi Din [679]
Multiply the numerator and denominator by 4+5i
=[(2+3i)(4+5i)]/[(4-5i)(4+5i)] 
=[(8-15)+(12+10)i] / [16+25] <span>= [ -7 + 22i ] / [41] 
= (-7/41) + (22/41)i </span>
3 0
3 years ago
In the after school Dena, Shawn, and Amanda knit scarfs that are the same size with yellow, white, and blue yarn. Denas scarf is
jenyasd209 [6]

Answer:

\frac{8}{20}

Step-by-step explanation:

We have been given that in the after school Dena, Shawn, and Amanda knit scarfs that are the same size with yellow, white, and blue yarn. Denas scarf is 2/5 yellow, Shawn's scarf is 3/5 , and Amanda's scarf is 3/4 yellow.

To make Amanda's argument true, let us compare each fraction by making a common denominator.

We can see that least common denominator of each fraction would be 20.

\text{Dena's scarf}=\frac{2}{5}\Rightarrow\frac{2*4}{5*4}=\frac{8}{20}

\text{Shawn's scarf}=\frac{3}{5}\Rightarrow\frac{3*4}{5*4}=\frac{12}{20}

\text{Amanda's scarf}=\frac{3}{4}\Rightarrow\frac{3*5}{4*5}=\frac{15}{20}

Since \frac{8}{20} , therefore, Amanda's scarf has the most yellow.

8 0
3 years ago
the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
mamaluj [8]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:

<span>The interquartile range is the difference between the third and the first quartiles.

The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5

The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
4 0
2 years ago
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