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3 years ago

What is the scale factor from the original to A?

Mathematics

1 answer:

Nookie1986 [14]3 years ago

3 0

Answer:

Do you have a picture? If not, count how many squares on a coordinate plane of each shape and divide the image with the pre-image.

Step-by-step explanation:

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Write 6/16 in lowest terms

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Answer:

3/8

Step-by-step explanation:

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4 years ago

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Write 0.8 in simplest form fraction

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Listen .8 Is pronounced eight tenths or in fraction eight over ten then simplified to 4 over 5

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4 years ago

Estimate the square root of 397 between two consecutive whole numbers.

marshall27 [118]

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Step-by-step explanation:

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3 years ago

A recipe for 10 servings of raspberry sorbet calls for 2 cups of water, 1/1.2 cups of granulated sugar, and 4 cups of frozen ras

babunello [35]

We know that 16 cups are in 1 gallon
We also know that 10 servings = 2 cups

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3 years ago

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A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along

mina [271]

Answer:

The tip of the man shadow moves at the rate of $\frac{20}{3} ft.sec$

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

$\frac{y - x}{y} = \frac{6}{15}$

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = $\frac{15x}{9\\} y = \frac{5x}{3}$

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

$\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt}$ ----(1)

We are given $\frac{dx}{dt} = 4 ft/sec$ . Plug in the equation (1), we get

$\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec$

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

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3 years ago