How do you solve this problem 4÷8/9-1/2=
2 answers:
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Answer:
6. O+ to A+ donors = 90 to 45; 90 : 45 and 90/45
7. AB- donors to AB+ donors = 4 to 6; 4 : 6 and 4/6
8. B+ to total donors = 20 to 195; 20 : 195 and 20/195
9. O- donors to A- donors = 9 to 21; 9 : 21 and 9/21
10. B- donors to B+ donor = 0 to 20; 0 : 20 and 0/20
11. O- donors to total donors = 9 to 195; 9 : 195 and 9/195
12. A+ donors and B+ donors to AB+ donors = 65 to 6; 65 : 6 and 65/6
13. A- donors and B- donors to AB- donors = 21 to 4; 21 : 4 and 21/4
14. the ratio 90/9 is a comparison of O+ donors to O- donors
Step-by-step explanation:
A ratio is a relationship where for every x unit of one quantity there are y units of another quantity. A ratio can be written in three ways:
x to y
x:y, or
x/y
For the given questions;
6. O+ to A+ donors = 90 to 45; 90 : 45 and 90/45
7. AB- donors to AB+ donors = 4 to 6; 4 : 6 and 4/6
8. B+ to total donors = 20 to 195; 20 : 195 and 20/195
9. O- donors to A- donors = 9 to 21; 9 : 21 and 9/21
10. B- donors to B+ donor = 0 to 20; 0 : 20 and 0/20
11. O- donors to total donors = 9 to 195; 9 : 195 and 9/195
12. A+ donors and B+ donors to AB+ donors
A+ donors and B+ donors to = 45 + 20 = 65
therefore, A+ donors and B+ donors to AB+ donors = 65 to 6; 65 : 6 and 65/6
13. A- donors and B- donors to AB- donors
A- donors and B- donors = 21 + 0= 21
therefore, A- donors and B- donors to AB- donors = 21 to 4; 21 : 4 and 21/4
14. O+ donors = 90; O- donors = 9
therefore, the ratio 90/9 is a comparison of O+ donors to O- donors
Answer:
In 2026 car will have a value of $5,000.
Step-by-step explanation:
We have been given that Jack bought a new car in 2014 for 28,000. If the value of the car decreases by 14% each year.
Since we know that an exponential function is in form: , where,
a = Initial value,
b = For decay or decrease b is in form (1-r), where r represents decay rate in decimal form.
Let us convert our given decay rate in decimal form.
Upon substituting a =28,000 and r=0.14 in exponential decay function we will get,
, where x represents number of years after 2014.
Therefore, the function represents the value of car x years after 2014.
To find the number of years it will take to car have the value of $5,000, we will substitute y=5,000 in our function.
Let us divide both sides of our equation by 28,000.
Let us take natural log of both sides of our equation.
Using natural log property we will get,
As in the 12th year after 2014 car will have a value of $5,000, so we will add 12 to 2014 to find the year.
Therefore, in 2026 car will have a value of $5,000.