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denis-greek [22]

3 years ago

5

How do i get 51 with the numbers 5, 6, 7, 8? Must use all of the numbers and only can use addition, subtraction, multiplication,

or division.

1 answer:

exis [7]3 years ago

8 0

Answer:

(8-5)*(6+7+(8-6)+(7-5))

Step-by-step explanation:

You might be interested in

Nick is now seven times as old as harry. In 6 years , nick will be five times as old as harry. How old will harry be in 6 years?

gizmo_the_mogwai [7]

X = Harry's Age

Nick's age is 7x

In 6 years Harry is 7x+6, and Nick is 5(x+6)

7x+6=5x+30

2x+6=30

2x = 24

x = 12

Harry = 12 years old and in 6 years Harry will be 18.

4 0

4 years ago

Read 2 more answers

In a certain chemical, the ratio of zinc to copper is 3 to 13. A jar of the chemical contains 286 grams of copper. How many gra

iren2701 [21]

Answer:

The jar of chermical contains 66g of Zinc.

Step-by-step explanation:

The ratio of Zinc to Copper is 3 : 13

A jar of the chemical contains 286g of copper.

Let the mass of the Zinc be xg.

$\frac{13}{3}$ = $\frac{286}{x}$

x = $\frac{3 × 286}{13}$ = 66g

So the jar of chemical contains 66g of Zinc.

8 0

3 years ago

A system has two failure modes. One failure mode, due to external conditions, has a constant failure rate of 0.07 failures per y

nadya68 [22]

Answer:

0.9177

Step-by-step explanation:

let us first represent the two failure modes with respect to time as follows

R₁(t) for external conditions

R₂(t) for wear out condition ( Wiebull )

Now,

$R1(t) = e^{-nt} .....1$

where t = time in years = 1,

n = failure rate constant = 0.07

Also,

$R2(t)=e^{-(\frac{t}{Q} )^{B} }......2$

where t = time in years = 1

where Q = characteristic life in years = 10

and B = the shape parameter = 1.8

Substituting values into equation 1

$R1(t) = e^{-(0.07)(1)} \\\\R1(t) = e^{-0.07}$

Substituting values into equation 2

$R2(t)=e^{-(\frac{1}{10} )^{1.8} }\\\\R2(t)=e^{-(0.1)}^{1.8} }\\\\R2(t)=e^{-0.0158}$

let the <em>system reliability </em>for a design life of one year be Rs(t)

hence,

Rs(t) = R1(t) * R2(t)

t = 1

$Rs(1) = [e^{-0.07} ] * [e^{-0.0158} ] = 0.917713$

Rs(1) = 0.9177 (approx to four decimal places)

5 0

3 years ago

A cone has a diameter of 12 ft and a slant height of 20 ft. Explain whether tripling both dimensions would triple the surface ar

Ratling [72]

<span>Tripling both dimensions would NOT triple the surface area. If you triple both dimensions, then the surface area is 9 times as long as the surface area of original cone.</span>

8 0

3 years ago

For some postive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770. The value of Z is

Talja [164]

Answer:

1.16

Step-by-step explanation:

Given that;

For some positive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770.

This implies that:

P(0<Z<z) = 0.3770

P(Z < z)-P(Z < 0) = 0.3770

P(Z < z) = 0.3770 + P(Z < 0)

From the standard normal tables , P(Z < 0) =0.5

P(Z < z) = 0.3770 + 0.5

P(Z < z) = 0.877

SO to determine the value of z for which it is equal to 0.877, we look at the

table of standard normal distribution and locate the probability value of 0.8770. we advance to the left until the first column is reached, we see that the value was 1.1. similarly, we did the same in the upward direction until the top row is reached, the value was 0.06. The intersection of the row and column values gives the area to the two tail of z. (i.e 1.1 + 0.06 =1.16)

therefore, P(Z ≤ 1.16 ) = 0.877

8 0

3 years ago