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denis-greek [22]

3 years ago

5

How do i get 51 with the numbers 5, 6, 7, 8? Must use all of the numbers and only can use addition, subtraction, multiplication,

or division.

1 answer:

exis [7]3 years ago

8 0

Answer:

(8-5)*(6+7+(8-6)+(7-5))

Step-by-step explanation:

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(2, -4) and (6,-10)<br> find the midpoint of the segment

asambeis [7]

The midpoint of the segment:
(4, 7)
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5 0

3 years ago

2 numbers whose sum is 23 and difference is -81

xz_007 [3.2K]

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3 years ago

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blagie [28]

Answer: 37

Step-by-step explanation:

4 0

3 years ago

800 shared into the ratio of 9:13:18

9966 [12]

Ratio 9:13:18......added = 40. This means that one person gets 9/40 of the total, one person gets 13/40 of the total and one person gets 18/40 of the total.

and if the total is 800...

9/40 * 800 = 7200/40 = 180 <==
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4 0

3 years ago

Pls help :)) this question is confusing for me :)

Temka [501]

Given:

$y^{2}(2 y-5)-8 y+20$

To find:

The product of the expression.

Solution:

$y^{2}(2 y-5)-8 y+20=y^{2}(2 y-5)+(-8 y+20)$

Take out -4 as a common factor in Last two terms.

$=y^{2}(2 y-5)-4(2 y-5)$

Make sure the terms in both brackets must be same.

Take out common factor (2y - 5) from both terms.

$=(2 y-5)(y^{2}-4)$

4 can be written as 2².

$=(2 y-5)\left(y^{2}-2^2\right)$

Using the identity: $(a^2-b^2)=(a-b)(a+b)$

$=(2 y-5)(y-2)(y+2)$ .

The product is $(2 y-5)(y-2)(y+2)$ .

5 0

3 years ago