R(r1+r2)=r1r2 How do I solve for r
1 answer:
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Answer:
C.
Step-by-step explanation:
it is to be noted that the question is only asking for the probability of the 2nd card given that the first card was queen , and not asking for the probability of 1st card to be queen and 2nd card to be faced card
we can represent it in an expression:
here P(Q) is the first event: Queen
and P(F|Q) is the second event: Faced card, given that the Queen is taken
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we only need to know what is P(F|Q), and that can be found directly found:
let's start with P(Q), what is the probability that the first card is a Queen? Well, there are 4 queens in a standard deck of 52 cards, so the probability should be:
now we have taken our queen, but we haven't put it back in the deck. so the amount of cards in the deck now are 51.
let's calculate P(F|Q),now that one queen is taken out, what is the probability of the next card to be a faced card? Well, in a standard deck there are 12 faced cards, but in our case one queen is already taken out, so there are 11 faced cards in our deck!
and this our answer!