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3 years ago

R(r1+r2)=r1r2 How do I solve for r

Mathematics

1 answer:

Studentka2010 [4]3 years ago

7 0

The answer is r = 0,3

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. The volume of a box is 405 cubic units. The length is x units, the width 4 units greater than the length, and the height is 9

lukranit [14]

Answer:

length = 5

width = 9

Step-by-step explanation:

V = lwh

let 'x' = length

let '4+x' = width

9 = height

405 = 9x(4+x)

405 = 36x + 9x²

this is a quadratic equation: 9x² + 36x - 405 = 0

factor out a 9 to get:

9(x² + 4x - 45) = 0

9(x-5)(x+9) = 0

one root is 5 and the other is -9

since distance cannot be negative we use 5 as the length and 9 is the width

3 0

2 years ago

SOLVE: 12x - 4y = 48 (For y in terms of x)

Anna71 [15]

First, we subtract 12x from both sides. We then get -4y=-12x+48. We then divide this by -4 on both sides to get the y by itself. We then get that the equation is y=3x-12.

7 0

3 years ago

HELP PLSS I DONT WANNA FAIL

posledela

Answer: 1/2 and 3/6

Explanation: 1/2 is equal to 3/6 because if you divide both 3 and 6 by 2 it’s 1/2

Not sure about 4

3 0

2 years ago

A real estate company wants to build a parking lot along the side of one of its buildings using 800 feet of fence. If the side a

Elden [556K]

Answer:

80,00 $ft^{2}$

Step-by-step explanation:

According to my research, the formula for the Area of a rectangle is the following,

$A = L*W$

Where

A is the Area
L is the length
W is the width

Since the building wall is acting as one side length of the rectangle. We are left with 1 length and 2 width sides. To maximize the Area of the parking lot we will need to equally divide the 800 ft of fencing between the <u>Length and Width.</u>

800 / 2 = 400ft

So We have 400 ft for the length and 400 ft for the width. Since the width has 2 sides we need to divide 60 by 2.

400/2 = 200 ft

Now we can calculate the maximum Area using the values above.

$A = 400ft*200ft$