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Anna11 [10]
3 years ago
14

What is the slope of the line represented by the equation y= -1/2x+1/4​

Mathematics
2 answers:
almond37 [142]3 years ago
5 0

Answer:

-1/2

Step-by-step explanation:

The format your equation in is called slope-intercept form:

y=mx+b

m stands for slope, the slope basically determines how much the line is tilted. b stands for the y intercept, the y intercept is when the line intercepts with the y axis.

Your equation is:

y= <u>-1/2</u>x+1/4

y=   <u>m</u> x+ b

Olegator [25]3 years ago
4 0
X=1/2 I’m mostly guessing but for math just use the app called photo math it’s helps with math equations but not math written problems
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√(- 9 ) / (( 4 - 7 i ) - ( 6 - 6 i )) = 3 i / ( 4 - 7 i - 6 + 6 i ) =
= 3 i / ( - 2 - i ) = - 3 i / ( 2 + i ) =
= \frac{-3i}{2 + i}* \frac{2 - i}{2 - i}= \\ =   \frac{-6i+3i ^{2} }{2- i^{2} }= \\ = \frac{-3-6i}{2+1}= \frac{-3-6i}{3}=
= - 1 - 2 i

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3 years ago
I already solved this but I'm confused if the answer is A or C?
irinina [24]
The answer is C. a 4.5 feet, b. 30 feet
8 0
2 years ago
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In a certain​ country, the true probability of a baby being a girl is 0.469. Among the next seven randomly selected births in th
-BARSIC- [3]

Answer:

The probability is 0.995 ( approx ).

Step-by-step explanation:

Let X represents the event of baby girl,

The probability of a baby being a girl is, p = 0.469,

So, the probability of a baby who is not a girl is, q = 1 - 0.469 = 0.531,

Also, the total number of experiment, n = 7

Thus, by the binomial distribution formula,

P(x)=^nC_x(p)^x q^{n-x}

Where, ^nC_x=\frac{n!}{x!(n-x)!}

The probability that all babies are girl or there is no baby boy,

P(X=7)=^7C_7(0.469)^7(0.531)^{7-7}

=0.00499125661758

Hence, the probability that at least one of them is a boy​ = 1 - P(X=7)

= 1 - 0.00499125661758

= 0.995008743382

≈ 0.995

8 0
3 years ago
The number 28 please somebody help me...
MArishka [77]
Where is the persons info
8 0
3 years ago
PLEASEE HELP!
melamori03 [73]

Answer:

Two non zero vectors, a and b are parallel when they are scalar multiples of each other such that a = c·b where c is a scalar quantity.

Therefore, in order to find a vector that is parallel to the vector, b = (-2, -1), we multiply the vector, b by a scaler quantity

Step-by-step explanation:

Given that the vector b = (-2, -1) can be written as follows;

b = -2·i - j, we have;

\left | b \right | = √((-2)² + (-1)²) = √5

Therefore, we have;

The coordinates of the endpoint of the vector are (-2, 0) and (0, -1)

Therefore, the slope of the vector = (-1 - 0)/(0 - (-2)) = -1/2

The slope of parallel vectors are equal, which gives the slope of the parallel vector = -1/2 = (λ × (-1 - 0))/(λ ×(0 - (-2))

Therefore, a parallel vector is obtained from a vector by multiplying with a scaler product.

7 0
3 years ago
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