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aivan3 [116]
3 years ago
13

7.Sabrina wants to deposit $3,066 into savings accounts at three different banks: Bank of the US,

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
7 0

The amount Sheila deposits in the Bank of US saving account is $511.

Sabrina has a total of $3,066 she wants to deposit. She has three banks that she wants to deposit her money in.

Let, a represent the amount she would deposit she would invest 7/4 bank.

The amount invested in Catch bank = 6 x a = 6a

The amount invested in Bank of US = 20% x ( 6a + a)

= 0.2 x 7a

= 1.4a

The total amount invested in the three banks can be represented with this equation:

1.4a + a + 6a = 3066

In order to determine the amount she would save in the Bank of US, the amount deposited in 7/4 bank has to be determined first.

8.4a = 3066

a = $365

The amount deposited in the Bank of US = 1.4a

= 1.4 x 365

= $511

A similar question was answered here: brainly.com/question/2289204?referrer=searchResults

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How many pairs of consecutive natural numbers have a product of less than 40000? I am in 5th grade. This is supposed to be easy
Ugo [173]

Answer:

There are 199 pairs of consecutive natural numbers whose product is less than 40000.

Step-by-step explanation:

We notice that such statement can be translated into this inequation:

n \cdot (n+1) < 40000

Now we solve this inequation to the highest value of n that satisfy the inequation:

n^{2}+n < 40000

n^{2}+n -40000

The Quadratic Formula shows that roots are:

n_{1,2} = \frac{-1\pm\sqrt{1^{2}-4\cdot (1)\cdot (-40000)}}{2\cdot (1)}

n_{1,2} = -\frac{1}{2}\pm \frac{1}{2} \cdot \sqrt{160001}

n_{1} = -\frac{1}{2}+\frac{1}{2}\cdot \sqrt{160001}

n_{1} \approx 199.501

n_{2} = -\frac{1}{2}-\frac{1}{2}\cdot \sqrt{160001}

n_{2} \approx -200.501

Only the first root is valid source to determine the highest possible value of n, which is n_{max} = 199. Each natural number represents an element itself and each pair represents an element as a function of the lowest consecutive natural number. Hence, there are 199 pairs of consecutive natural numbers whose product is less than 40000.

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Answer:

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Step-by-step explanation:

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