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shutvik [7]
3 years ago
13

Plz answer mhanifa!

Mathematics
1 answer:
wel3 years ago
5 0

Answer:

I'm not mhanifa, but I am also really good at math (i'm in accelerated math rn) so I will try to help too.

Step-by-step explanation:

My tips:

1. Try to focus on formula's not small things like answers or definitions (they are still important but be more focused on formulas), this will really help you when you need to solve eqautions.

2. Don't over-study. Basically don't overload yourself with information, focus on the major things, if you overload yourself, you may not remember everything, and that would not be very helpful at all.

3. Don't try to study the things you are good at, study the things you struggle with, this will help you ALOT.

4. Take your time, you don't want to mess up because you are rushing, and you know math is really annoying and you can get the answer wrong for one incorrect calculation.

5. Get your sleep, this is very important

I hope this helps!! good luck on your EOG!!!!!!

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What is the area of a triangle with a base of 7 mm and a height of 10 mm
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Step-by-step explanation:

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Please help!! x = 2 - 3 cos t, y = 1 + 4 sin t in rectangular form?<br><br> thank you! :)
sukhopar [10]

Answer:

\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1

Step-by-step explanation:

x=2-3\cos(t)

y=1+4\sin(t)

Let's solve for \cos(t) in the first equation and then solve for \sin(t) in the second equation.

I will then use the following identity to get right of the parameter, t:

\cos^2(t)+\sin^2(t)=1 (Pythagorean Identity).

Let's begin with x=2-3\cos(t).

Subtract 2 on both sides:

x-2=-3\cos(t)

Divide both sides by -3:

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Now time for the second equation, y=1+4\sin(t).

Subtract 1 on both sides:

y-1=4\sin(t)

Divide both sides by 4:

\frac{y-1}{4}=\sin(t)

Now let's plug it into our Pythagorean Identity:

\cos^2(t)+\sin^2(t)=1

\frac{x-2}{-3})^2+(\frac{y-1}{4})^2=1

\frac{(x-2)^2}{(-3)^2}+\frac{(y-1)^2}{4^2}=1

\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1

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