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3 years ago

Plz answer mhanifa!

Mathematics

1 answer:

wel3 years ago

5 0

Answer:

I'm not mhanifa, but I am also really good at math (i'm in accelerated math rn) so I will try to help too.

Step-by-step explanation:

My tips:

1. Try to focus on formula's not small things like answers or definitions (they are still important but be more focused on formulas), this will really help you when you need to solve eqautions.

2. Don't over-study. Basically don't overload yourself with information, focus on the major things, if you overload yourself, you may not remember everything, and that would not be very helpful at all.

3. Don't try to study the things you are good at, study the things you struggle with, this will help you ALOT.

4. Take your time, you don't want to mess up because you are rushing, and you know math is really annoying and you can get the answer wrong for one incorrect calculation.

5. Get your sleep, this is very important

I hope this helps!! good luck on your EOG!!!!!!

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Israel added $120 to his savings. This added amount represents 1/6 of his total savings. If s represents the total savings, whic

oee [108]

Calculista Ambitious

the correct question in the attached figure

Let

s----------> total savings

case a) Israel added $80 to his savings

we know that

80=(1/8)*s-------> multiply by 8 both sides------> s=$640

the answer case a) is

the equation is

80=(1/8)*s

case b) Israel added $120 to his savings

we know that

120=(1/8)*s-------> multiply by 8 both sides------> s=$960

the answer case b) is

the equation is

120=(1/8)*s

Read more on Brainly.com - brainly.com/question/10503464#readmore

7 0

3 years ago

Weights of cars passing over a bridge part 2<br>

DaniilM [7]

Step-by-step explanation:

The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.

Given:

mean, mu = 3550 lbs (hope I read the first five correctly, and it's not a six)

standard deviation, sigma = 870 lbs

weights are normally distributed, and assume large samples.

Probability to be estimated between W1=2800 and W2=4500 lbs.

Solution:

We calculate Z-scores for each of the limits in order to estimate probabilities from tables.

For W1 (lower limit),

Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069

From tables, P(Z<Z1) = 0.194325

For W2 (upper limit):

Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954

From tables, P(Z<Z2) = 0.862573

Therefore probability that weight is between W1 and W2 is

P( W1 < W < W2 )

= P(Z1 < Z < Z2)

= P(Z<Z2) - P(Z<Z1)

= 0.862573 - 0.194325

= 0.668248

= 0.67 (to the hundredth)

6 0

3 years ago

Please explain with working!!! Find the set of values of x that satisfy the inequality 9x^2-15x<6

Oksi-84 [34.3K]

Answer:

$-1/3$

Step-by-step explanation:

When solving a quadratic inequality, first solve it normally like you would for a normal quadratic equation. We have:

$9x^2-15x$

Ignore the less than sign and replace it with an equal sign and solve the quadratic for its zeros:

$9x^2-15x=6$

Subtract 6 from both sides:

$9x^2-15x-6=0$

Divide everything by 3:

$3x^2-5x-2=0$

Factor. Find two numbers that equal (3)(-2)=-6 that add up to -5.

-6 and 1 works. Thus:

$3x^2-6x+x-2=0\\3x(x-2)+1(x-2)=0\\(3x+1)(x-2)=0$

Find the x using the Zero Product Property:

$3x+1=0 \text{ or }x-2=0\\x=-1/3\text{ or }x=2$

Now, we need to replace the equal signs with symbols again. To do so, we need to test which symbol to place. Let's do the first zero first.

So, the first zero is:

$x=-1/3$

Assume that the correct symbol is >. Thus,

$x>-1/3$

Now, pick any number that is greater than -1/3. I'll pick 0 since it's the easiest. Now, plug 0 back into the very original inequality. If it works, then the sign is correct, if it doesn't, then simply use the opposite one. Therefore:

$9x^2-15x$

0 is indeed less than six, so our first correct solution is:

$x>-1/3$

For the second one, do the same thing. We have:

$x=2$

Assume that the correct symbol is <. Thus:

$x$

Again, pick any number less than 2. I'm going to use 0. Plug 0 back into the original equation

$9x^2-15x$

Again, this is correct. Therefore, x<2 is also the correct inequality.

So together, we have:

$x>-1/3 \text{ and } x$

Together, we can write them as:

$-1/3$

(Note that we don't need to worry about the "or equal to" part since the original inequality didn't have it.)

6 0

3 years ago

For the equation given below, evaluate y′ at the point (−2,2)<br> xe^y−4y=2x−4−2e^2

jeka94

Implicit differentiation
chain rule is important here

I'll show the steps partially
$e^y+xe^yy'-4y'=2$
$xe^yy'-4y'=2-e^y$
$y'(xe^y-4)=2-e^y$
$y'=\dfrac{2-e^y}{xe^y-4}$
now evaluate for (-2,2)
x=-2 and y=2
$y'=\dfrac{2-e^2}{-2e^2-4}$
$y'=\dfrac{2-e^2}{-2e^2-4}$
$y'=\dfrac{e^2-2}{2e^2+4}$
that's it, simplest form

3 0

3 years ago

Find the value of y so that line is passing through two points

Alenkinab [10]

Slope of a line passing through two given points
= (y2-y1)/(x2-x1)

For m=3, and substituting coordinates,
3=(1-y)/(4-1)
solve for y
1-y=3*3=9
y=1-9=-8

Answer: y=-8

6 0

3 years ago