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prisoha [69]
3 years ago
6

The symbol ∪ represents the union of events. The union of two events A and B results in an event that contains all the sample po

ints of event A or event B or both events. Therefore, A ∪ B is a new event that lists the sample points of event A or event B or both events. Recall the set notation used for an event with k sample points. event = {sample point 1, sample point 2, , sample point k} Event A is made up of the sample points E1, E4, and E6 and event B is made up of the sample points E2, E4, and E7. Thus, the union of events A and B will have what sample points that are contained in either A or B?
Mathematics
1 answer:
Degger [83]3 years ago
8 0

Answer:

AUB = {E1, E2, E4, E6, E7}

Step-by-step explanation:

Since we are to look for the union of the two sets, therefore we combine all the sample points that are contained in A and B without repeating any sample even if such sample occur in both sets. For example, E4 occurs in event A and B and as such will only be repeated once in the union of the two events.

AUB = {E1, E2, E4, E6, E7}

Note that the way you arrange does not matter as well.

I hope you find this solution useful?

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A farmer had twice as many chickens as ducks on his farm. After he sold 166 chickens and ducks, he had half as many chickens as
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Answer:

The farmer have at first <u>202</u> chickens.

Step-by-step explanation:

Given:

A farmer had twice as many chickens as ducks on his farm. After he sold 166 chickens and ducks, he had half as many chickens as ducks left.

Now, to find the chickens farmer have at first.

Let the chickens be x.

And, the ducks be y.

<em>As, the farmer had twice as many chickens as ducks on his farm.</em>

So, x=2y    ......(1)

<em>As, given the farmer after selling 166 chickens and ducks, he had half as many chickens as ducks left.</em>

According to question:

x-166=(y-29)\times \frac{1}{2}

x-166=\frac{y-29}{2}

Substituting the value of x from equation (1) we get:

2y-166=\frac{y-29}{2}

<em>By cross multiplying we get:</em>

4y-332=y-29

<em>Adding both sides 332 we get:</em>

4y=y+303

<em>Subtracting both sides by </em>y<em> we get:</em>

3y=303

<em>Dividing both sides by 3 we get:</em>

y=101.

Now, to get the number of chickens substituting the value of y in equation (1):

x=2y\\\\x=2\times 101\\\\x=202.

Therefore, the farmer have at first 202 chickens.

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