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3 years ago

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Mathematics

2 answers:

shusha [124]3 years ago

7 0

Answer:

-36.

Step-by-step explanation:

First term a1 = 21.

Common difference d = 18 - 21 = -3 (15-18 = -3)

nth term an = a1 + (n - 1)d

So 20th term = 21 + (20-1) -3

= 21 - 3 * 19

= 21 - 57

= -36.

mixas84 [53]3 years ago

4 0

Answer:

-36

Step-by-step explanation:

-3

-6

-9

-12

-15

-18

-21

-24

-27

-30

-33

-36

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docker41 [41]

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3 years ago

Please answer this question now

Tema [17]

Answer:

Surface Area = 85.75 ft²

Step-by-step explanation:

Surface area of pyramid = ½(Perimeter of triangular base * slant height of pyramid) + Area of triangular base

Perimeter of triangular base = sum of all sides of the triangular base = 5+5+5 = 15 ft

Slant height of pyramid = 10 ft

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4 years ago

Examplelt: A wall of length 10 m was to be built across an open ground. The height of the wall is 4 m and thickness of the wall

harina [27]

Answer :

4167 bricks.

Explanation :

Since the wall with all its bricks makes up the space occupied by it, we need to find the volume of the wall, which is nothing but a cuboid.

Here,

${\qquad \dashrightarrow{ \sf{Length=10 \: m=1000 \: cm}}}$

$\qquad \dashrightarrow{ \sf{Thickness=24 \: cm}}$

$\qquad \dashrightarrow{ \sf{Height=4 m=400 \: cm}}$

Therefore,

${\qquad \dashrightarrow{ \bf{Volume \: of \: the \: wall = length \times breadth \times height}}}$

${\qquad \dashrightarrow{ \sf{Volume \: of \: the \: wall = 1000 \times 24 \times 400 \: {cm}^{3} }}}$

Now, each brick is a cuboid with Length = 24 cm, Breadth = 12 cm and height = 8 cm.

So,

${\qquad \dashrightarrow{ \bf{Volume \: of \: each \: brick = length \times breadth \times height}}}$

${\qquad \dashrightarrow{ \sf{Volume \: of \: each \: brick = 24 \times 12 \times 8 \: {cm}^{3} }}}$

So,

${\qquad \dashrightarrow{ \bf{Volume \: of \: bricks \: required = \dfrac{volume \: of \: the \: wall}{volume \: of \: each \: brick} }}}$

${\qquad \dashrightarrow{ \sf{Volume \: of \: bricks \: required = \dfrac{1000 \times 24 \times 400}{24 \times 13 \times 8} }}}$

${\qquad \dashrightarrow{ \sf{Volume \: of \: bricks \: required = \bf \: 4166.6} }}$

Therefore,

The wall requires 4167 bricks.

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