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Anarel [89]
2 years ago
10

Andrew pays a monthly membership fee of $10 at his gym. Each time he uses the gym, he pays $5. Last month, Andrew spent a total

of $65 for membership and gym use. If the equation 10 + 5 x = 65 models the situation, how many times did he use the gym last month?
11
12
13
15
Mathematics
1 answer:
umka2103 [35]2 years ago
8 0

Answer:

First step to solving the equation is to subtract 10 on both sides:

10 - 10 + 5x =65 -10

5x = 55

Then, we divide by 5 on both sides!

5x ÷ 5 = 55 ÷ 5

x = 11

Our result is 11, so the answer to the problem is 11

I hope I was helpful!

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sesenic [268]

Answer:

The answer should be D.

Hope this helped, have a nice day!


4 0
3 years ago
Solve this please, will mark brainliest
satela [25.4K]

Answer: 6 cm,22.9 cm, 20.1 cm

Step-by-step explanation:

6 0
3 years ago
How do I solve this math problem?
Alina [70]
You would subtract 11 on both sides of the equation.
Then multiply the reciprocal of 1/2 which is 2.
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6 0
3 years ago
Read 2 more answers
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Sedbober [7]

Answer:I know you said no PDFs but I know this site that can help you. Just search up ‘Desciptive Statistics Calculator’ it can help you a lot

Step-by-step explanation:

7 0
3 years ago
Johnson Chemicals is considering two options for its supplier portfolio. Option 1 uses two local suppliers. Each has a "unique-e
sashaice [31]

Answer:

a) P=0.0175

b) P=0.0189

Step-by-step explanation:

For both options we have to take into account that not only the chance of a "superevent" will disable both suppliers.

The other situation that will disable both is that both suppliers have their "unique-event" at the same time.

As they are, by definition, two independent events, we can calculate the probability of having both events at the same time as the product of both individual probabilities.

a) Then, the probability that both suppliers will be disrupted using option 1 is

P_1=P_{se}+P_{ue}^2=0.015+(0.05)^2=0.015+0.0025=0.0175

b) The probability that both suppliers will be disrupted using option 2:

P_2=P_{se}+P_{ue}^2=0.002+(0.13)^2=0.002+0.0169=0.0189

Pue = probability of a unique event

Pse = probability of a superevent

3 0
3 years ago
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