Answer:
From the picture attached,
9). When pre-image KLMN is a reflected across x = -2, we get image K'L'M'N'.
Therefore, line of reflection will be x = -2
10). In this picture line of reflection which passes through origin (0, 0) and slope = 1 will be,
y = x.
11). Since, all the points of image and preimage points are equidistant from x-axis, line of reflection will be x-axis or y = 0.
12). Line passing through midpoint of the line joining BB' will be the line of reflection.
Coordinates of B → (5, 3)
Coordinates of B' → (5, 7)
Coordinates of BB' → → (5, 5)
Therefore, line of reflection will be y = 5.
13). Coordinates of G → (2, 5)
Coordinates of G' → (-2, 5)
Midpoint joining the segment GG' → → (0, 5)
Therefore, line of reflection → x = 0
14). Line of reflection passing through (0, 0) and slope = -1
y = -x
Step-by-step explanation:
(reflexive property)
(tangents drawn from a common external point are congruent)
(right angles are congruent)
