Answer:
a. After the first bounce, the ball will be at 85% of 8 ft. After 2 bounces, it'll be at 85% of 85% of 8 feet. After 3 bounces, it'll be at (85% of) (85% of) (85% of 8 feet). You can see where this is going. After n bounces the ball will be at

b. After 8 bounces we can apply the previous formula with n = 8 to get
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c. The solution to this point requires using exponential and logarithm equations; a more basic way would be trial and error using the previous
increasing the value of n until we find a good value. I recommend using a spreadsheet for that; the condition will lead to the following inequality:
Let's first isolate the fraction by dividing by 72.
Now, to get numbers we can plug in a calculator, let's take the natural logarithm of both sides:
. Now the two quantities are known - or easy to get with any calculator, replacing them and solving for n we get:
Now, since n is an integer - you can't have a fraction of a bounce after all, you pick the integer right after that, or n>27.
Answer:
D. x <= -3 or x >= 5
Step-by-step explanation:
3 | x-1 | > = 12
3(x - 1) >= 12
3x - 3 >= 12
3x >= 15
x >= 5
or
-3(x - 1) >= 12
-3x + 3 >= 12
-3x >= 9
x <= -3
Answer
x <= -3 or x >= 5
Answer:
The degrees of freedom are given by:

The p value for this case would be given by:
Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes
Step-by-step explanation:
Information given
represent the sample size
represent the confidence level
represent the sample variance
represent the value that we want to verify
System of hypothesis
We want to test if the true deviation for this case is lesss than 5minutes, so the system of hypothesis would be:
Null Hypothesis:
Alternative hypothesis:
The statistic is given by:
And replacing we got:
The degrees of freedom are given by:

The p value for this case would be given by:
Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes
The area is c 38.3 units 2