The answer is
t dy / dt + dy / dt = te ^ y
I apply common factor 1/dt*(tdy+dy)=te^y
I pass "dt" tdy+dy=(te^y)*dt
I apply common factor (t+1)*dy=(te^y)*dt
I pass "e^y" (1/e^y)dy=((t+1)*t)*dt
I apply integrals ∫ (1/e^y)dy= ∫ (t^2+t)*dt
by property of integrals ∫ (1/e^y)dy= ∫ (e^-y)dy
∫ (e^-y)dy= ∫ (t^2+t)*dt
I apply integrals
-e^-y=(t^3/3)+(t^2/2)+C
I apply natural logarithm to eliminate "e"
-ln (e^-y)=-ln(t^3/3)+(t^2/2)+C
y=ln(t^3/3)+(t^2/2)+C
Answer:
B
Step-by-step explanation:
The standard form of a circle is
where h and k are the coordinates of the center of the circle and the radius is squared. The radius is easy...take the square root of 25 to get that the radius is 5. Since the pattern for the standard form is "x-" and "y-", if (x+2)^2 is the horizontal placement of the center, it actually was originally written as (x-(-2))^2, so the h coordinate is -2. Same goes for the vertical movement of the center. (y-(5))^2 means that the k coordinate is a positive 5.
I WOULD SAY C IS THE CORRECT ANSWER
So f(x)=x+10 lets say
so if you put something into the function lets say 5 then the function will do something to it and give you an answer so if you put in 5 for x you would get 5+10 or 15
a function of a function
lets say
f(x)=2x-9
g(x)=7x+2
(g(x) is just another function represented by g instead of f)
so if you wanted to put g(x) as x into f(x) and put x in g(x) to 3
then f(g(x))=2(7x+2)-9 or f(g(3))=2(7*3+2)-9=2(23)-9=37
hope this helps
ANSWER
Vertical shift: 3 units down.
Maximum value: -2
Minimum value: -4
EXPLANATION
The given sine function is ;
The vertical shift is 3 units down.
The maximum value is 1+-3=-2
The minimum value is -1-3=-4