Which function is a horizontal compression of its parent function f(x)= x^2 by a factor of 4
1 answer:
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Answer: If we define 2:00pm as our 0 in time; then:
at t= 0. the velocity is 30 mi/h.
then at t = 10m (or 1/6 hours) the velocity is 50mi/h
Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:
a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/
Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)
So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/
Answer:
1. -4
2. 6
3. -6
(i hope this is right •_•)
Step-by-step explanation:
<u>First table</u>
When the x coordinate is 0, that point is your y intercept. For the first one, your y intercept is -4.
<u>Second table</u>
For the second one, we need to do a bit of counting. We can see the x coordinates go before and after zero, but the table does not show us 0. So, we're going to have to calculate the slope. Bear with me here, I'm a little tired and this might be rambling ;-;
So, the formula for calculating slope is . I'm going to use those first two points to get my slope. We're going to say the first point is point 1 and the second point is point 2 (genius, i know lol). So, let's substitute in the x and y values.
And simplify...
So, your slope is -1. We can use that. We just have to count down.
If the x is -2, the y is 8. If the x is -1, the y is 7. And if the x is 0....(drumroll please) the y is 6! So, your y intercept is 6.
<u>Third table</u>
Now, this table isn't very nice either and doesn't have an x as 0 for us. Hmpf. But we can still do what we did above. I'll just skip the explanation and you can observe my steps.
Let's count down....
If x = 3, y = -5
If x = 2, y = -5 1/3
If x = 1, y = -5 2/3
If x = 0, y = -6