Answer:
28
Step-by-step explanation:
So this means to replace the r you see in 4r^2-8 with 3.
Let's do that:
4(3)^2-8
Now to simplify this just use pemdas or a calculator:
4(9)-8 since 3^2 means 3*3=9
36-8
28
Answer:
- A. g(x) =
![\sqrt[3]{x - 4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%20-%204%7D)
Step-by-step explanation:
<u>Given function</u>
Graphed is, horizontal translation right 4 units.
<u>This is:</u>
or
- g(x) =
![\sqrt[3]{x - 4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%20-%204%7D)
Correct choice is A
I conclude that the sum will be even because any even number can be represented by 2n where n is a whole number
and even numbers are 2 apart, so
the sum of the first 15 are
2n+2(n+1)+2(n+2) etc until we get to 2(n+14)
we can undistribute the 2 from all of them and get
2(n+n+1+n+2...n+14)
and we are sure that whatever is in the parenthasees is a whole number because whole+whole=whole
therefor, the sum is even
if you did want to find the sum then
an=2n
the 15th even number is 30
the first is 2
S15=15(2+30)/2=15(32)/2=15(16)=240
which is even
We are going to round the number '3'.
Look at the first number to the right of '3', which is '9'.
That number is greater than '5', so you round the '3' to '4', and add three zeros after '4'.
Answer is: 4,000