Answer:
1. N4 = a
2. N8.25 = b
Step-by-step explanation:
1000 litre =N3
Each additional 100 litres = 5 k
100 litres
2000 litres
100 litres =5k
2000 litres = x
100x =5×2000
100x =10,000
Divide both sides of the equation by 100
x = 100k
100 Kobo = N1
x =N1
N3+N1 =N4
2. First ten words cost N6
Each additional word cost 45 k
1= 45k
5=x
x = 5×45
= 225 Kobo
100 Kobo = 1 Naira
225 Kobo = x
x = N2.25
N6 + N2.25
x = N8.25 = B
Due to the u-shaped graph suggested by these data points, this would best be matched with a quadratic function.
Answer: -18
<u>Explanation:</u>
Average rate of change is slope:
. Need to find the y-coordinates:
g(x) = -x² - 4x
g(6) = -(6)² - 4(6)
= -36 - 24
= -60
⇒ (6, -60)
g(8) = -(8)² - 4(8)
= -64 - 32
= -96
⇒ (8, -96)
m = 
= 
= -18
Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions (
)
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME=
where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME=
≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5