The distance between the campsite and the rest area is 9 miles.
The given parameters:
- <em>Initial speed of the campers, u = 4.5 mph</em>
- <em>Final speed of the campers, v = 4 mph</em>
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Let the time of motion from the campsite to rest area = t (hours)
Time for return trip = t hours + 15 mins
= (t + 0.25) hours
Let the distance between the campsite and rest area = d
d = 4.5t
d = 4(t + 0.25)
4.5t = 4(t + 0.25)
4.5t = 4t + 1
4.5t - 4t = 1
0.5t = 1
t = 2 hours
The distance between the campsite and the rest area is calculated as follows;
d = 4.5t
d = 4.5 x 2
d = 9 miles
Thus, the distance between the campsite and the rest area is 9 miles.
Learn more about distance and speed here: brainly.com/question/2854969
The answer is D. Analyse the value of a borrowers home and cars to be used as collateral for a loan.
Answer:
-For the Protection of Literary and Artistic Works/Berne Convention
-For the protection of computer codes and programs/WIPO copyright treaty
-For the inventor for making, using, offering for sale, and selling the invention/US Patent Law
-for copyright holders to reproduce, distribute, or preform their own work/ Copyright Act of 1976
Explanation:
