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Serjik [45]
3 years ago
13

PPPPPPPPPPPPPPLLLLLLLLLLLLEEEEEEEEEEEEEEAAAAAAAAAAASSSSSSSEEEEEEE

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
8 0

Answer:

Theres no picture?

Step-by-step explanation:

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Find the slope of the line that passes through the points (10, 9) and (2, 4).
solniwko [45]

Answer:

slope = 5/8

Step-by-step explanation:

use the slope formula to find the slope: \frac{y_2 - y_1}{x_2-x_1}

\frac{9-4}{10-2} = \frac{5}{8}

6 0
2 years ago
Triangle FGH is similar to triangle IJK. Find the measure of side KI. Round your
erastovalidia [21]

Answer:

5.8

Step-by-step explanation:

Similar shapes also maintain a constant proportion of sides. Therefore, we can set up the following equation:

\frac{31}{43}=\frac{\text{KI}}{8}

Solving, we get:

\text{KI}=\frac{8\cdot 31}{43}\approx \boxed{5.8}

5 0
3 years ago
Work out the acceleration for the first 3 seconds?
Finger [1]

The acceleration is given by the slope of the line. This line passes through the points (0, 2) and (3, 5), so it has slope

\dfrac{5-2}{3-0}=1

which means the acceleration over this 3 second interval is 1 m/s^2.

5 0
3 years ago
Read 2 more answers
Write the equation of the line that passes through (-6,0) and is parallel to the line y=5x-43
AVprozaik [17]

The equation of the line that passes through (-6,0) and is parallel to the line y = 5x - 43 in slope intercept is y = 5x + 30

<em><u>Solution:</u></em>

Given that line that passes through (-6, 0) and is parallel to the line y = 5x - 43

We have to find the equation of line

Let us first find slope of line having equation y = 5x - 43

<em><u>The slope intercept form of line is given as:</u></em>

y = mx + c  ------- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

On comparing equation of line y = 5x - 43 with slope intercept form y = mx + c,

we get m = 5

Thus slope of given line is 5

We know that slopes of parallel lines are equal

Thus the slope of line parallel to given line is also 5

Now let us find equation of line having slope "5" and passes through (-6, 0)

Substitute m = 5 and (x, y) = (-6, 0) in eqn 1

y = mx + c

0 = 5(-6) + c

<h3>c = 30</h3>

<em><u>Thus the required equation is:</u></em>

Substitute c = 30 and m = 5 in eqn 1

y = 5x + 30

Thus the required equation of line is found

8 0
2 years ago
Susan started her homework at 1{:}59\text { p.M.}1:59 p.M.1, colon, 59, start text, space, p, point, m, point, end text and fini
inn [45]

Answer:

Step-by-step explanation:

Susan started her homework at = 1:59 pm

She took time = 96 mins

Time at which she had volleyball practice = 4:00 pm

So, time between her starting of homework and starting of volleyball is given by

1:59 pm to 4:00 pm = 2 hrs and 1 mins

2 hr 1 min = 120 mins + 1 min = 121 mins

But she took 96 mins to do her homework, so

Out of 121 mins, 96 mins she took for homework

Remaining time = 121 mins - 96 mins = 25 mins

Therefore, time Susan had between finishing her homework and the beginning of volleyball practice is 25 mins

7 0
3 years ago
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