Question

(2a-b) * (a-2b) (4x - 2) * (x -4)

Answer 1

Q: (2a-b) * (a-2b)

$(2−)(−2)$

$2(−2)+(−2)(−)$

$22−4+(−2)(−)$

$22−4−(−2)⋅$

$22−4+22−⋅$

Q: (4x - 2) * (x -4)

$(4−2)(−4)$

$4(−4)−2(−4)$

$42−16−2(−4)$

$42−16−2+8$

$42−16−2+8$

$42−18+8$

$42−18+8$

Hope its help you !!

Answer 2

You are going to want to FOIL both of these (first, outside, inside, last).

(2a-b)(a-2b)
=2a^2-4ab-ab+2b^2
=2a^2-5ab+2b^2

I’ll break it down more with the second equation. Remember that ^2 means squared.

(4x-2)(x-4)
First: 4x*x= 4x^2
Outside: 4x*-4=-16x
Inside: -2*x=-2x
Last: -2*-4=8

Now let’s put the answers together in one equation.

4x^2-16x-2x+8

Now we will combine like terms.

4x^2-18x+8