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xxMikexx [17]
2 years ago
5

Please help me on this I don’t understand it 3i+(3/4+2i)-(3+3i)

Mathematics
1 answer:
Katyanochek1 [597]2 years ago
4 0

Answer:

A

Step-by-step explanation:

By my mean

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What is the remainder when (x3 − 7x2 − 18x + 42) is divided by (x + 3)?
Vitek1552 [10]
Look at the picture.
The remainder is 6.

3 0
3 years ago
Read 2 more answers
27/64A bottled water company has designed a new cup for its dispenser. The cup will be a right circular cone with a three-inch r
tankabanditka [31]

Answer:

9.86 inches

Step-by-step explanation:

Given:

The cup will be a right circular cone with:-

Radius, r = 3 inches

Volume of cone = 93 cubic inches

Height of the cup, h = ?

Solution:

<u>By using :-</u>

<u />Volume\ of\ right\ circular\ cone=\frac{1}{3} \pi r^{2} h

                                            93 =\frac{1}{3} \times\frac{22}{7} \times3\times3\times h\\ \\ 93=\frac{198}{21} h\\ \\ 93=9.43h

By dividing both sides by 9.43

\frac{93}{9.43} =\frac{9.43h}{9.43} \\ \\ 9.86\ inches=h

Thus, the cup need to be 9.86 inches taller to hold 93 cubic inches of water.

6 0
3 years ago
A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300. The
zubka84 [21]

Answer:

the variance of the refund payment to the couple = 9463.394

Step-by-step explanation:

Given that :

A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300.

It is possible that the couple won't be able to refund up 100 per day or more than 100 per day.

SO; let assume that the refund payment happens to be 0, 100,200,  300

Let X be the total refund payment on the seven day cruise.

We can say  X = 0, if there is no rain on all 7 days.

P(X = 0) = _nC_x * P^x * (1 - P)n-x

P(X = 0) =  _7C_o * 0.2^0 * (1-0.2)^{7-0

P(X = 0) =1 * 1* (1-0.2)^{7

P(X = 0) =(0.8)^{7

P(X = 0) =0.2097152

If it rains on any one day; then X = 100

P(X = 100) = _nC_x * P^x * (1 - P)n-x

P(X = 100) =  _7C_1 * 0.2^1 * (1-0.2)^{7-1

P(X = 0) =7 * 0.2* (1-0.2)^{6

P(X = 100) =7* 0.2* (0.8)^{6

P(X = 100) =0.3670016

if it rains on any two day  ; then X = 200

P(X = 200) = _nC_x * P^x * (1 - P)n-x

P(X = 200) =  _7C_2 * 0.2^2 * (1-0.2)^{7-2

P(X = 200) =  21 * 0.2^2 * (0.8)^{5

P(X = 200) = 0.2752512

if it rains on any three day or more than that ; then X = 300

P(X \ge 300) = 1 - P(X < 300)  \\ \\ P(X \ge 300) = 1 - [P(X = 0) + P(X = 100) + P(X = 200)] \\ \\ P(X \ge 300) = 1 - [0.2097152 + 0.3670016 + 0.2752512] \\ \\ P(X \ge 300) = 0.148032

Now; we have our probability distribution function as:

P(X = 0) = 0.2097152

P(X = 100) = 0.3670016

P(X = 200) = 0.2752512

P(X = 300) = 0.148032

In order to determine the variance of the refund payment to the couple; we use the formula:

variance of the refund payment to the couple[Var X] =E [X^2] - (E [X])^2

where;

E[X^2]  = \sum x^2 \times p \\ \\ E[X^2]  = 0^2 * 0.2097152 + 100^2 * 0.3670016 + 200^2 * 0.2752512 + 300^2 * 0.148032 \\ \\  E[X^2]  = 0  + 3670.016 + 11010.048+ 13322.88  \\ \\  E[X^2]  =28002.944

(E [X]) = \sum x * p\\ \\  (E [X]) =  0 * 0.2097152 + 100 * 0.3670016 + 200 * 0.2752512 + 300 * 0.148032 \\ \\ (E [X]) = 0 + 36.70016 + 55.05024 + 44.4096\\ \\ (E [X]) = 136.16 \\ \\ (E [X])^2 = 136.16^2 \\ \\ (E [X])^2 = 18539.55

NOW;

the variance of the refund payment to the couple = 28002.944 - 18539.55

the variance of the refund payment to the couple = 9463.394

7 0
2 years ago
There are three pieces of pizza how many 1/4 pieces of pizza can be sliced from the 3 pieces
Lapatulllka [165]
3/4 can be sliced from three pieces
3 0
3 years ago
At an amusement park , the cost of 3 adult tickets and 4 children’s ticket is $126.50 another customer paid $120.50 for 2 adult
KonstantinChe [14]

Answer:

1 Adult ticket=$21.50 ; 1 Children ticket=$15.50

Step-by-step explanation:

3A+4C=126.50

2A+5C=120.50

We find the price of adult tickets 1st.

15A+20C=632.5

8A+20C=482

7A=632.5-482=150.5

1A=21.50

Now we find Children ticket

6A+8C=253

6A+15C=361.50

7C=108.50

1C=15.50

4 0
3 years ago
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