All categories

2 years ago

A map scale is give as 1:10000

Mathematics

1 answer:

Fynjy0 [20]2 years ago

6 0

Answer:

2km

Step-by-step explanation:

You might be interested in

In a circus performance, a monkey is strapped to a sled and both are given an initial speed of 3.0 m/s up a 22.0° inclined track

Aloiza [94]

Answer:

Approximately $0.31\; \rm m$ , assuming that $g = 9.81\; \rm N \cdot kg^{-1}$ .

Step-by-step explanation:

Initial kinetic energy of the sled and its passenger:

$\begin{aligned}\text{KE} &= \frac{1}{2}\, m \cdot v^{2} \\ &= \frac{1}{2} \times 14\; \rm kg \times (3.0\; \rm m\cdot s^{-1})^{2} \\ &= 63\; \rm J\end{aligned}$ .

Weight of the slide:

$\begin{aligned}W &= m \cdot g \\ &= 14\; \rm kg \times 9.81\; \rm N \cdot kg^{-1} \\ &\approx 137\; \rm N\end{aligned}$ .

Normal force between the sled and the slope:

$\begin{aligned}F_{\rm N} &= W\cdot \cos(22^{\circ}) \\ &\approx 137\; \rm N \times \cos(22^{\circ}) \\ &\approx 127\; \rm N\end{aligned}$ .

Calculate the kinetic friction between the sled and the slope:

$\begin{aligned} f &= \mu_{k} \cdot F_{\rm N} \\ &\approx 0.20\times 127\; \rm N \\ &\approx 25.5\; \rm N\end{aligned}$ .

Assume that the sled and its passenger has reached a height of $h$ meters relative to the base of the slope.

Gain in gravitational potential energy:

$\begin{aligned}\text{GPE} &= m \cdot g \cdot (h\; {\rm m}) \\ &\approx 14\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \times h\; {\rm m} \\ & \approx (137\, h)\; {\rm J} \end{aligned}$ .

Distance travelled along the slope:

$\begin{aligned}x &= \frac{h}{\sin(22^{\circ})} \\ &\approx \frac{h\; \rm m}{0.375}\end{aligned}$ .

The energy lost to friction (same as the opposite of the amount of work that friction did on this sled) would be:

$\begin{aligned} & - (-x)\, f \\ = \; & x \cdot f \\ \approx \; & \frac{h\; {\rm m}}{0.375}\times 25.5\; {\rm N} \\ \approx\; & (68.1\, h)\; {\rm J}\end{aligned}$ .

In other words, the sled and its passenger would have lost (approximately) $((137 + 68.1)\, h)\; {\rm J}$ of energy when it is at a height of $h\; {\rm m}$ .

The initial amount of energy that the sled and its passenger possessed was $\text{KE} = 63\; {\rm J}$ . All that much energy would have been converted when the sled is at its maximum height. Therefore, when $h\; {\rm m}$ is the maximum height of the sled, the following equation would hold.

$((137 + 68.1)\, h)\; {\rm J} = 63\; {\rm J}$ .

Solve for $h$ :

$(137 + 68.1)\, h = 63$ .

$\begin{aligned} h &= \frac{63}{137 + 68.1} \approx 0.31\; \rm m\end{aligned}$ .

Therefore, the maximum height that this sled would reach would be approximately $0.31\; \rm m$ .

7 0

3 years ago

Mrs. Johnson put 22,250 miles

Viefleur [7K]

The change in quantities can be represented as percentage

<em>The percentage decrease in miles driven is 34.83%</em>

The given parameters are:

$\mathbf{Initial = 22250}$

$\mathbf{Final = 14500}$

The percentage decrease is calculated as:

$\mathbf{\%Decrease = \frac{Final - Initial}{Initial} \times 100\%}$

Substitute known values

$\mathbf{\%Decrease = \frac{14500- 22250}{22250} \times 100\%}$

$\mathbf{\%Decrease = \frac{-7750}{22250} \times 100\%}$

$\mathbf{\%Decrease = \frac{-775000}{22250} \%}$

$\mathbf{\%Decrease = -34.83 \%}$

The negative sign implies that, the change represents a decrement.

Hence, the percentage decrease in miles driven is 34.83%

Read more about percentage change at:

brainly.com/question/14801224

7 0

2 years ago

En un huerto se siembra frijol. Si se pone una planta, produce 3kg de frijol. por cada planta extra que se ponga, todas las plan

Ad libitum [116K]

Answer:

y = -0.07x2 + 3.07x

Step-by-step explanation:

For each plant we add, there is a decrease of 70 grams for all plants from the inicial value of 3 kg of beans.

So, for 2 plants, we have (3 - 0.07) * 2

For 3 plants, we have (3 - 2*0.07) * 3

For x plants, we have (3 - (x-1)*0.07) * x

So we can model the final result of the amount of beans 'y' with the equation:

y = (3 - (x-1)*0.07) * x

y = (3 - 0.07x + 0.07) * x

y = (3.07 - 0.07x) * x

y = -0.07x2 + 3.07x

(In this equation we have a = -0.07, b = 3.07 and c = 0)

7 0

3 years ago

The cost of a layer cake is $17 plus $5 per layer. If Paul has only $30 to spend on a cake, what is the most number of layers he

VikaD [51]

Answer:

The most number of layers he can afford is 2

Step-by-step explanation:

We automatically have a fee of 17 so we know we have 13 dollars remaining. Using this information, we know that one layer is 5 dollars which means we can get 2 layers which is equal to 10 dollars which turns our total fee to $27. Hope this helps!

5 0

4 years ago

Read 2 more answers

Area of plane and composite figures

Phoenix [80]

Dont click the link they track your ips

6 0

3 years ago