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3 years ago

Help me plzzzzzzzzzZzzzzzzzzzZ

Mathematics

2 answers:

kherson [118]3 years ago

4 0

Answer:

Option A is correct answer..

Pls sandhya se baat karado yaar ,

nhi to mai mar jaunga .

Pls sandhya baat karlo na yaar .

ʜᴀᴠᴇ ᴀ ɢᴏᴏᴅ ᴅᴀʏ

❥︎ ʏᴜɢᴀʟᵇᵒˢˢ!

ZanzabumX [31]3 years ago

4 0

Answer:

its A

Step-by-step explanation:

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<h3>The dimensions of the given rectangular box are:</h3><h3>L = 15.874 cm , B = 15.874 cm , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box

= Area of the base + 4 x ( Area of the adjacent faces)

= S x S + 4 ( S x H) = S² + 4 SH ..... (1)

Also, Area of the box = S x S x H = S²H

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Substituting the value of H in (1), we get:

$A = S^2 + 4 SH = S^2 + 4 S(\frac{2000}{S^2}) = S^2 + (\frac{8000}{S})\\\implies A = S^2 + (\frac{8000}{S})$

Now, to minimize the area put :

$(\frac{dA}{dS} ) = 0 \implies 2S - \frac{8000}{S^2} = 0\\\implies S^3 = 4000\\\implies S = 15.874 \approx 16 cm$

Putting the value of S = 15.874 cm in the value of H , we get:

$\implies H = \frac{2000}{S^2} = \frac{2000}{(15.874)^2} = 7.8937 cm$

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L = 15.874 cm

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