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belka [17]
2 years ago
9

IS MY ANSWER CORRECT??? *IF NOT PLEASE TELL ME THE CORRECT ONE, ITS FOR A QUIZ! *

Mathematics
1 answer:
olga nikolaevna [1]2 years ago
7 0

Answer:

Correct answer please mark me brainliest answer

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The following graph shows a proportional relationship.
Mice21 [21]
I think that if you use 2 and 3 I think you have to mutually understand the difference between 3 and 2
6 0
3 years ago
Find the volume of a square pyramid with base edges of 30 cm and a slant height of 39 cm
belka [17]

Answer:

390cm

Step-by-step explanation:

5 0
3 years ago
A van travels 150 miles on 6 gallons of gas. How many gallons will it need to travel 325 miles?
shtirl [24]
<h3>Answer:  C) 13 gallons</h3>

============================================================

Work Shown:

(150 miles)/(6 gallons) = (325 miles)/(x gallons)

150/6 = 325/x

150*x = 6*325 .... see note below

150x = 1950

x = 1950/150 .... divide both sides by 150

x = 13 gallons is the final answer

-----------

Note: in this step, I cross multiplied. The general template for cross multiplication is that we go from A/B = C/D to A*D = B*C. As the name implies, the "cross" refers to the "X" shape that forms when you multiply the terms.

6 0
3 years ago
Read 2 more answers
4/5G + 42 = 2.8G + 18<br> Plz solve with an explanation
inysia [295]

Answer:

12

Step-by-step explanation:

Simplify  \frac{4}{5}G

​5

​

​4

​​ G  to  \frac{4G}{5}

​5

​

​4G

​​ .

\frac{4G}{5}+42=2.8G+18

​5

​

​4G

​​ +42=2.8G+18

Multiply both sides by 5.

4g + 210 = 14g + 90

Simplify  

 14G + 90 - 4G to 10G + 90

Subtract 90 from both sides.

210-90=10G210−90=10G

Simplify  210-90210−90  to  120120.

120=10G120=10G

Divide both sides by 1010.

\frac{120}{10}=G

​10

​

​120

​​ =G

Simplify  \frac{120}{10}

​10

​

​120

​​   to  1212.

12=G12=G

Switch sides.

G=12G=12

SORRY ABOUT ALL THIS WORK...

3 0
3 years ago
Read 2 more answers
-12°F+ -23°F please don't let me down
coldgirl [10]

Plus a negative value becomes subtraction:

-12 + -23 = -12 -23 = -35

3 0
3 years ago
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