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gogolik [260]
3 years ago
8

Cot x sec4x = coy x + 2 tan x + tan3x

Mathematics
1 answer:
Fantom [35]3 years ago
7 0

Answer:

Step-by-step explanation:

Simplify RHS

Cotx +2tanx+tan^3x

Cotx/sinx+2(sinx/cosx)+sin^3x/cos^3x

Taking LCM

(cos^4x+2sin^2xcos^2x+sin^4x)/sinx cos^3x

(Cos^2x+sin^2x)^2/sinx cos^3x

(1/sinx cos^3x)

(1/sinx cos^3x)*(cosx/cosx)

Cotx sec^4x

LHS=RHS

Hence proved

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rusak2 [61]

Answer:

The measure of one of the acute angles is 22 degrees, and the measure of the other acute angle is 68 degrees.

Step-by-step explanation:

The angles of a triangle add up to 180 degrees; we know this by the Sum of Angles of a Triangle Theorem.

Then one angle is marked as a right angle meaning it has a measure of 90 degrees.

Using this information and the labels on the diagram we can set up an equation:

x+3x+2+90=180

Now we can solve for x.

4x+92=180

4x=88

x=22 degrees

The measure of one of the acute angles is 22 degrees.

Now to solve for the measure of the other acute angle.

Subsitute the value of x first.

x=22

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The measure of the other acute angle is 68 degrees.

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nikdorinn [45]

Answer:

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A is correct

Step-by-step explanation:

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