Answer:
a = 
x = 27y
Step-by-step explanation:
Order of Operations: BPEMDAS
<u>Question 1</u>
Step 1: Write out discriminant
d = b² - 4ac
Step 2: Subtract b² on both sides
d - b² = -4ac
Step 3: Divide both sides by -1
b² - d = 4ac
Step 4: Divide both sides by 4c
a =
<u>Question 2</u>
Step 1: Write out equation
2/3(x - 18y) = 6y
Step 2: Distribute parenthesis
2/3x - 12y = 6y
Step 3: Isolate <em>x </em>by adding 12y on both sides
2/3x = 18y
Step 4: Divide both sides by 2/3
x = 27y
Answer:
x = (-27)/11
Step-by-step explanation:
Solve for x:
(-11 x)/54 - 1/2 = 0
Put each term in (-11 x)/54 - 1/2 over the common denominator 54: (-11 x)/54 - 1/2 = (-27)/54 - (11 x)/54:
(-27)/54 - (11 x)/54 = 0
(-27)/54 - (11 x)/54 = (-11 x - 27)/54:
(-11 x - 27)/54 = 0
Multiply both sides of (-11 x - 27)/54 = 0 by 54:
(54 (-11 x - 27))/54 = 54×0
(54 (-11 x - 27))/54 = 54/54×(-11 x - 27) = -11 x - 27:
-11 x - 27 = 54×0
0×54 = 0:
-11 x - 27 = 0
Add 27 to both sides:
(27 - 27) - 11 x = 27
27 - 27 = 0:
-11 x = 27
Divide both sides of -11 x = 27 by -11:
(-11 x)/(-11) = 27/(-11)
(-11)/(-11) = 1:
x = 27/(-11)
Multiply numerator and denominator of 27/(-11) by -1:
Answer:x = (-27)/11
Answer:
third option is the correct answer
go with the names of the triangle
the triangles are HIJ and LMN
so the ratios will be accordingly
If Sachiko lets x represent the length of the side of the square and she wants to find the length of the perimeter of the square, it is appropriate for her to ...
... B. Set the area equal to x², solve for x, and then multiply the value of x by 4.
_____
The area of a square of side length x is x·x = x². The perimeter of a square of side length x is x+x+x+x = 4·x.
Answer:
P' (- 7, - 5 )
Step-by-step explanation:
A translation of 3 units to the left means subtractin 3 from the x- coordinate with no change to the y- coordinate, thus
P(- 3, 5 ) → (- 3 - 4, 5 ) → (- 7, 5 )
Under a reflection in the x- axis
a point (x, y ) → (x, - y ), thus
(- 7, 5 ) → P'(- 7, - 5 )
