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4 years ago

30 POINTS why are 3/4 and 6/8 equivalent

1 answer:

3 0

Step-by-step explanation: In order to decide whether the given fractions are equivalent, first write each fraction in lowest terms. Remember, a fraction is written in lowest terms if the greatest common factor of the numerator and the denominator is 1.

For our first fraction which is 3/4, the greatest common factor of 3 and 4 is 1, the fraction is already in lowest terms.

For our second fraction however, since the greatest common factor of 6 and 8 is 2, we must divide both the numerator and denominator by 2 which gives us 3/4.

3/4 = 3/4 which means these fractions are equivalent.

3/4 and 6/8 are equivalent because if you reduce 6/8 in lowest terms, you end up with the fraction 3/4.

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A painter leans a 15-ft ladder against a house.

kiruha [24]

Let the height be h
According to the Pythagoras Theorem,
h= root 15^2-5^2
= root 225-25
= root 200= 14.14
Thus, the ladder reaches approximately 14.14 feet from the base of the house

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3 years ago

17+17+17+17+17+1764638292836362729=

Mazyrski [523]

Answer:

1.7646383e+18

Step-by-step explanation:

mark me as brainliest pls :)

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3 years ago

Read 2 more answers

Evaluate the following [7]-[9-3]

pochemuha

Do 9-3 first to get 6. Next, do 7-6. The answer is 1.

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3 years ago

F(x) = x2 – 3x – 2 is shifted 4 units left. The result is g(x). What is g(x)?

Ray Of Light [21]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now... your expression is not in vertex form, that's ok... to do a horizontal shift to the left by 4 units, we can simply, add the C and B component to the "x" variable, C=4, B =1, that way the horizontal shift of C/B or 4/1 is just +4, giving us a horizontal shift to the left

$\bf f(x)=x^2-3x-2\impliedby \textit{let's change that for }f(1x+4)
\\\\\\
f(1x+4)=(1x+4)^2-3(1x+4)-2
\\\\\\
f(x+4)=x^2+8x+16-3x-12-2
\\\\\\
f(x+4)=x^2-5x+2\impliedby g(x)$

8 0

3 years ago

Read 2 more answers

5ab^2 - 12a^2b + 3ab + ab^2 + 4a^2b

Agata [3.3K]

Answer:

(a) 6ab² - 8a²b + 3ab

Step-by-step explanation:

Given: 5ab² - 12a²b + 3ab + ab² + 4a²b

In this question, we will be combining like terms.

What are like terms?

Like terms are terms with the same variables and power. For example, 2x and 4x, as well as 2a² and 4a².

Combine like terms:

5ab² - 12a²b + 3ab + ab² + 4a²b

(5ab² + ab²) + (-12a²b + 4a²b) + 3ab

6ab² - 8a²b + 3ab

4 0

2 years ago