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SOVA2 [1]
2 years ago
5

When a flash of lightning occurs, the number of seconds elapsed until thunder is heard can be used to approximate the distance f

rom the storm. The graph models this situation. Which equation can be used to approximate the distance from a storm, y , in miles, given the number of seconds, x , that has elapsed from the moment that a flash of lightning is seen to the time thunder is heard?

Mathematics
2 answers:
inn [45]2 years ago
6 0
Pretty sure its C :)
denis-greek [22]2 years ago
5 0
After you see a flash of lightning, count the number of seconds until you hear the thunder. (Use the stop watch or count "One-Mississippi, Two-Mississippi, Three-Mississippi," etc.) For every 5 seconds the storm is one mile away. Divide the number of seconds you count by 5 to get the number of miles.

It’s y=1/5x
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Find the quotient 5/18 divided by 2/6
Gnesinka [82]
5/18 diveded by 2/6 is 5/18*6/2 then its 5/18 * 3 which gives 15/18 or 5/6 
7 0
3 years ago
Meghan earns 20.00 dollars by walking dogs. She uses all of her earnings to buy a shirt for 12.85 dollars and some stickers for
PIT_PIT [208]

Answer:

She bought 11 stickers

Step-by-step explanation:

20 - 12.85

7.15

then

7.15/0.65

11

6 0
3 years ago
Read 2 more answers
The equation of a circle is (x + 6)^2 + (y - 4)^2 = 16. The point (-6, 8) is on the circle.
pantera1 [17]

Answer:

y = 8 is the equation of tangent.

Step-by-step explanation:

The equation of the tangent to the circle at (-6,8) is of the form:

y = mx + c

where m is the slope of the tangent and c is the y-intercept.

The point (-6,8) lies on the circle and the tangent line as well.

Hence (-6,8) satisfies the line equation:

8 = m(-6) + c ⇒ c-6m = 8 -------------1

We know that slope of two perpendicular lines are related as:

m_{1}\times m_{2}=-1

At any point on the circle, the normal line at a point is always perpendicular to the tangent line at that point.

Hence :

m_{normal} \times m_{tangent}=-1

We can find the slope of the normal at point (-6,8) as it passes through the centre of the circle (-6,4) by using the two-points formula for slope.

m=\frac{y_2-y_1}{x_2-x_1}

         =\frac{8-4}{-6+6}

          = ∞

Slope of the normal is infinity and hence slope of tangent is -1/∞ = 0

Hence m=0

Putting m=0 in equation 1 we get:

c = 8

The equation of tangent line at (-6,8) is:

y = 8

6 0
3 years ago
The perimeter of a rectangle is 42 inches, and its area is 110 square inches. find the length and width of the rectangle.
lorasvet [3.4K]
p = 2w + 2l              p = 42 
a = l * w                   a = 108

You want to make either the length or width variable (I chose the width variable to be by itself. It doesn't matter) by itself by:

Divide both sides by 2.
(p) ÷ 2 = (2w + 2l) ÷ 2 
               2's  cancel  out
\frac{p}{2} = w + l

Subtract both sides by either length or width depending on what variable you chose to make by itself (in this case I subtracted the length variable because I wanted the width variable by itself).
\frac{p}{2} - l = w + l - l
                 l's  cancel  out 
p/2 - l = w

a = l * w

You replace w with the equation above p/2 - l = w 
a = l( \frac{p}{2} - l)

Multiply out the L.
a = \frac{p}{2}l - l^{2}

Plug in all your numbers a = 110 and p = 42
110 = \frac{42}{2}l - l^{2}
110 = 21l - l^{2

Move everything to the left side so l^{2} would be positive (makes the equation easier when l^{2} is positive).
l^{2} - 21l + 110 = 0

Factor.
(l -10)(l-11) = 0

Make each parenthesis set equal to 0.
l-11=0     l-10=0

Add.
l = 11  l = 10

By doing this you solve for both the width and length so the answer is:
w = 11    L = 10
8 0
3 years ago
What is the rounding or compatible number<br><br> of 256+321
Nana76 [90]
<span>Compatible </span>numbers for 256...
1. Rounded to the nearest hundred = 200
2. Rounded to the nearest tens place = 260

Compatible numbers for 321...
1. Rounded to the nearest hundred = 300
2. Rounded to the nearest tens place = 320

I hope this helps! :)


4 0
3 years ago
Read 2 more answers
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