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Mnenie [13.5K]
3 years ago
13

What is the rounding or compatible number of 256+321

Mathematics
2 answers:
cricket20 [7]3 years ago
5 0
256 would round to 300 and 321 would round to 300. 300+300 = 600
Hope thats what you were looking for!
Nana76 [90]3 years ago
4 0
<span>Compatible </span>numbers for 256...
1. Rounded to the nearest hundred = 200
2. Rounded to the nearest tens place = 260

Compatible numbers for 321...
1. Rounded to the nearest hundred = 300
2. Rounded to the nearest tens place = 320

I hope this helps! :)


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The parallel lines have the same slope.

The slope-intercept form: y = mx + b

m - a slope.

We have 6x + y = 4     |subtract 6x from both sides

y = -6x + 4 → m = -6.

The slope-point form:

y-y_1=m(x-x_1)

We have m = -6 and (-2, 3).

Substitute:

y-3=-6(x-(-2))\\\\y-3=-6(x+2)\\\\y-3=(-6)(x)+(-6)(2)\\\\y-3=-6x-12\qquad|+3\\\\y=-6x-9\qquad|+6x\\\\6x+y=-9

<h3>Answer: 6x + y = -9.</h3>
5 0
3 years ago
Given k(x) =x^3-2x, find k (3)
nadezda [96]

Answer:  21

Step-by-step explanation:

k(x) =x^3-2x

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3 years ago
2. Find mzR and mzS.<br> 89°<br> R<br> 157 T<br> Р
baherus [9]

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Step-by-step explanation:

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m of arc QRS = 2 m∠P = 2(57) = 114

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nata0808 [166]

Step-by-step explanation:

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Which graph represents the solution set to the system of inequalities? { y&lt;-1/2+2 y&gt;-3/2x+2
Sidana [21]

The graph of the given system of linear inequalities

y < -1/2 + 2

y > -3/2x + 2

is attached below

<h3>Graph of system of linear inequalities </h3>

From the given information, we are to graph the given system of linear inequalities

The given system of linear inequalities is

y < -1/2 + 2

y > -3/2x + 2

The graph of the given system of linear inequalities

y < -1/2 + 2

y > -3/2x + 2

is shown below

Learn more on Graph of system of linear inequalities here: brainly.com/question/26965469

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5 0
2 years ago
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