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Setler [38]
3 years ago
9

In order for the horticulture department have its Vegetables garden it needs to increase its field's phosphorus levels. Although

the nitrogen level doesn't need change.We would buy a bag of N-P-K fertilizer. Do we need a complete or incomplete fertilizer? .And why?​
Chemistry
1 answer:
krok68 [10]3 years ago
6 0

A COMPLETE FERTILISER BECAUSE OF THE PHOSPHORUS IN THE FIELD IS LIMITED. BUT DEPENDING ON THE OTHER NUTRITION IN THE SOIL. PLEASE MARK ME BRAINLIST

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Assuming 100% dissociation, calculate the freezing point and boiling point (in °C) of a solution with 83.6 g of AgNO 3 in 1.00 k
Thepotemich [5.8K]

Answer:

  • <u>Freezing point: - 1.83ºC</u>
  • <u>Boiling point: 100.50ºC</u>

Explanation:

The <em>freezing point</em> and<em> boiling point</em> of solvents, when a solute is added, will change accordingly to the concentration of the solute particles.

The freezing point will decrease and the boiling point will increase. These are two colligative properties.

<u></u>

<u>Find attached the file with the whole answer, as the site is not uploading the answer in here.</u>

Download pdf
3 0
4 years ago
Calcium carbide reacts with water to produce acetylene gas according to the following equation: CaC2(s) + 2H2O(l)C2H2(g) + Ca(OH
gtnhenbr [62]

Answer: The number of moles of CaC_2 reacted was 0.229

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = Total pressure - vapor pressure of water = (749 - 23.8) mm Hg= 725.2 mm Hg = 0.954 atm    (760mmHg= 1atm)

V = Volume of gas = 5.87 L

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =25^0C=(25+273)K=298K

n=\frac{PV}{RT}

n=\frac{0.954atm\times 5.87L}{0.0821 L atm/K mol\times 298K}=0.229moles

CaC_2(s)+2H_2O(l)\rightarrow C_2H_2(g)+Ca(OH)_2(aq)

According to stoichiometry:

1 mole of C_2H_2 is produced by = 1 mole of CaC_2

Thus 0.229 moles of C_2H_2 is produced by = \frac{1}{1}\times 0.229=0.229 moles of CaC_2

Thus number of moles of CaC_2 reacted was 0.229

5 0
3 years ago
Humans need gasoline for transportation, but using gasoline releases many pollutants. City government cab set policies to decrea
kolezko [41]

Answer:

Two policies that would most likely reduce gasoline use includes;

(1) Reduction in driving of vehicles such as having a bike sharing plan and

(2) Promoting only fuel efficient cars in the city such as electric cars

Explanation:

Policies that would decrease a city's gasoline usage includes

(1) Reduction in driving of vehicles such as having a bike sharing plan

(2) Limit on road worthiness of cars and restrictions on less fuel efficient habits

(3) Promoting only fuel efficient cars in the city such as electric cars

(4) Requirement to switch of vehicles when not moving

(5) Promoting optimal home deliveries

(6) Limiting other power devices to only fuel efficient models.

6 0
3 years ago
Read 2 more answers
Find the mass of a 60 ML volume of water if the density of water is 1 g/mL
valkas [14]

Answer:  60 grams

Explanation:  (60 ml)*(1g/ml) = 60g

3 0
3 years ago
Find the empirical formula of the following compounds:
Aneli [31]

The empirical formula of the following compounds 0.903 g of phosphorus combined with 6.99 g of bromine.

<h3>What is empirical formula?</h3>

The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula.

<h3>How to find the empirical formula?</h3>

Convert the given masses of phosphorus and bromine into moles by multiplying the reciprocal of their molar masses. The molar masses of phosphorus and bromine are 30.97 and 79.90 g/mol, respectively.

Moles phosphorus = 0.903 g phosphorus \frac{mol phosphorus}{ 30.97 g phosphorus}= 0.0293 mol

Moles bromine 6.99 g bromine\frac{mol bromine}{79.90 g bromine}=0.0875 mol

The preliminary formula for compound is P0.0293Bro.0875. Divide all the subscripts by the subscript with the smallest value which is 0.0293. The empirical formula is P1.00Br2.99 ≈ P₁Br3 or PBr3

To learn more about empirical formula visit:

brainly.com/question/14044066

#SPJ4

8 0
1 year ago
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