Answer:
- <u>Freezing point: - 1.83ºC</u>
- <u>Boiling point: 100.50ºC</u>
Explanation:
The <em>freezing point</em> and<em> boiling point</em> of solvents, when a solute is added, will change accordingly to the concentration of the solute particles.
The freezing point will decrease and the boiling point will increase. These are two colligative properties.
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Answer: The number of moles of
reacted was 0.229
Explanation:
According to ideal gas equation:

P = pressure of gas = Total pressure - vapor pressure of water = (749 - 23.8) mm Hg= 725.2 mm Hg = 0.954 atm (760mmHg= 1atm)
V = Volume of gas = 5.87 L
n = number of moles = ?
R = gas constant =
T =temperature =



According to stoichiometry:
1 mole of
is produced by = 1 mole of 
Thus 0.229 moles of
is produced by =
moles of
Thus number of moles of
reacted was 0.229
Answer:
Two policies that would most likely reduce gasoline use includes;
(1) Reduction in driving of vehicles such as having a bike sharing plan and
(2) Promoting only fuel efficient cars in the city such as electric cars
Explanation:
Policies that would decrease a city's gasoline usage includes
(1) Reduction in driving of vehicles such as having a bike sharing plan
(2) Limit on road worthiness of cars and restrictions on less fuel efficient habits
(3) Promoting only fuel efficient cars in the city such as electric cars
(4) Requirement to switch of vehicles when not moving
(5) Promoting optimal home deliveries
(6) Limiting other power devices to only fuel efficient models.
Answer: 60 grams
Explanation: (60 ml)*(1g/ml) = 60g
The empirical formula of the following compounds 0.903 g of phosphorus combined with 6.99 g of bromine.
<h3>What is empirical formula?</h3>
The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula.
<h3>
How to find the empirical formula?</h3>
Convert the given masses of phosphorus and bromine into moles by multiplying the reciprocal of their molar masses. The molar masses of phosphorus and bromine are 30.97 and 79.90 g/mol, respectively.
Moles phosphorus = 0.903 g phosphorus
= 0.0293 mol
Moles bromine 6.99 g bromine
=0.0875 mol
The preliminary formula for compound is P0.0293Bro.0875. Divide all the subscripts by the subscript with the smallest value which is 0.0293. The empirical formula is P1.00Br2.99 ≈ P₁Br3 or PBr3
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