Add EF and DE together to equal 32
2x-10 + 4x = 32
Combine like terms;
6x-10 = 32
Add 10 to each side:
6x = 42
Divide both sides by 6:
x = 42/6
X = 7
EF = 2x-10 = 2(7)-10 = 14-10 = 4
DE = 4x = 4(7) = 28
Answer: x=4
Step-by-step explanation:
We know that line segment AC= AB + BC
we also know that AB= 3x+8 and BC= 2x-5
by substituting these, we get AC= (3x+8)+(2x-5)
AC is given as being 23, so we know that
23= (3x+8)+(2x-5)
by combining like terms, we get that
5x+3=23
simplify this to get that x=4
Answer:
6(x+4)=30
6x+24=30
6x+24-24=30-24
x=6/6
x=1
Step-by-step explanation:
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Answer:
Step-by-step explanation:
The given sequence of numbers is increasing in geometric progression. The consecutive terms differ by a common ratio, r
Common ratio = 6/3 = 12/6 = 2
The formula for determining the nth term of a geometric progression is expressed as
Tn = ar^(n - 1)
Where
a represents the first term of the sequence.
r represents the common ratio.
n represents the number of terms.
From the information given,
a = 3
r = 2
The function, f(n), representing the nth term of the sequence is
f(n) = 3 × 2^(n - 1)
Answer: 5503680
Step-by-step explanation:
The coach wants 2 senior out of 36 so he have
C₃₆,₂ = 36!/( 36 - 2 )! = 36*35*34!/34! = 36 * 35 = 1260
possibilities
Now he also wants 3 juniors out of 14
C₁₄,₃ = 14!/ (14- 3)! = 14*13*12*11!/11! = 14*13*12 = 2184
Now for each pair of senior (from 1260 outcomes) coach has 2184 possiblities therefore
Coach has
2184 * 1260 = 2751840 possibilities to choose from
Again as there are 2 senior to choose for captain we have to multiply by 2 to get the total ways the team could be
2751840*2 = 5503680