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Eddi Din [679]
3 years ago
6

Keith works 8 hours per day for 5 days per week. Melba works 2,250 minutes each week. who spends more time at work?​

Mathematics
1 answer:
artcher [175]3 years ago
8 0
8 x 5 = 40

40 hours = 2400 minutes

2400>2250

Keith spends more time at work
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An employer at plant A receives a salary of 350 per week and 2.9% bonus on the production sales for the week
Vesnalui [34]
350+.029*5600= 350 + 162.40= 512.40
income for the week is $512.40
5 0
3 years ago
Which best describes the range of the function f(x) = 2/3(6)x after it has been reflected over the x-axis?
AlladinOne [14]
The function is f(x) = [2/3] [6^x]


It is an exponential function whose range is all the positive values. This is, for any value of x that exponential function yields a value that is greater than 0. The graph never crosses the x-axis.


When you reflect the function over the x-axis, you flip the graph over x, and you can see that the range of the new fucntion iis all the negative values, this is all the real numbers less than zero.


Answer: all the real numbers less than zero.
8 0
3 years ago
A circle is placed in a square with a side length of 16 yd. What is the area of the shaded region
Stels [109]

Answer:

64

Step-by-step explanation:

The formula for the perimeter (the distance around) a square is given by: P = 4s. = 16 m² is the area of the given square. That gives us A = 4^2 = 16.

7 0
3 years ago
Which of the following completes the proof?
adoni [48]

Answer:

  • 1. First blank: <u>∠ACB ≅ ∠E'C'D'</u>

  • 2. Second blank: <u>translate point E' to point A</u>

Therefore, the answer is the third <em>option:∠ACB ≅ ∠E'C'D'; translate point D' to point B</em>

Explanation:

<u>1. First blank: ∠ACB ≅ ∠E'C'D'</u>

Since segment AC is perpendicular to segment BD (given) and the point C is their intersection point, when you reflect triangle ECD over the segment AC, you get:

  • the image of segment CD will be the segment C'D'
  • the segment C'D' overlaps the segment BC
  • the angle ACB is the same angle E'C'D' (the right angle)

Hence: ∠ACB ≅ ∠E'C'D'

So far, you have established one pair of congruent angles.

<u>2. Second blank: translate point D' to point B</u>

You need to establish that other pair of angles are congruent.

Then, translate the triangle D'C'E' moving point D' to point B, which will show that angles ABC and E'D'C' are congruents.

Hence, you have proved a second pair of angles are congruent.

The AA (angle-angle) similarity postulate assures that two angles are similar if two pair of angles are congruent (because the third pair has to be congruent necessarily).

6 0
4 years ago
Read 2 more answers
Coach Roberts ordered 16 trophies from the Finish Line sports shop to give to each player at the end of the season. Since this w
jok3333 [9.3K]

Answer:

$12.50

Step-by-step explanation:

Divide the total amount by the number of trophies

152 ÷16 = 9.5

than add 3 to your total

9.5 + 3= 12.5

since where dealing with money add a zero and a dollar sign.

$12.50

5 0
3 years ago
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