Answer: time to reach maximum height = 605
Step-by-step explanation:
The expression that relates height with time is
M(d)=-0.123x^2+148.83x-21.07
Where time = x
d = height
The expression is a quadratic equation. If height of the object is plotted against time, the resulting graph is a parabola whose vertex is equal to the maximum height attained by the object. The time, x corresponding to the vertex is the time for it to reach maximum height.
To find x,
x = -b/2a
Where a= 0.123
b = 148.83
x = - 148.83 / -2 × -0.123
x = -148.83 / -0.246
= 605
Substituting x = 605 in the equation,
M(d)=-0.123x^2+148.83x-21.07
d = -0.123 × 605^2 + 148.83×605
= - 45021.075+ 90042.15
= 45020.4
Approximately 45000 feet
B. parallelogram , rhombus , and rectangle
Answer:
4,6,8,10
$10,$15,$20,$25
Step-by-step explanation:
Part A :
4,6,8,10
$10,$15,$20,$25
because the top row is adding by two and the bottom row is adding by 5
For the first one, you did good. I will just suggest a couple things.
Statement Reason
JK ≅ LM Given
<JKM ≅ < LMK Given (You did both of these steps so well done.)
MK ≅ MK Reflexive Property (Your angle pair is congruent but isn't one of the interior angle of the triangles you are trying to prove.)
ΔJMK ≅ ΔLKM SAS
Problem 2: (You also have a lot of great stuff here.)
Statement Reason
DE ║ FG Given
DE ≅ FG Given
<DEF≅<FGH Given
<EDF≅<GFH Corresponding Angles (You don't need to know that F is the midpoint but you got corresponding angle pair which is correct.)
ΔEDF≅ΔGFH ASA
<DFE≅<FHG CPCTC
Answer:
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Step-by-step explanation:
