No solution<span> would mean that there is </span>no<span> answer to the equation. It is impossible for the equation to be true </span>no<span> matter what value we assign to the variable. Infinite</span>solutions<span> would mean that any value for the variable would make the equation true.</span>No Solution<span> Equations.
</span>In other words, it "discriminates" between the possible solutions<span>. The discriminant is the expression found under the square root part of the quadratic formula (that is, . The value of tells how many </span>solutions<span>, roots, or x-intercepts the quadratic equation will have. If , there are two </span>real solutions<span>.</span>
Answer:
3m
Step-by-step explanation:
You can check
3m(4+x)
12m+3mx
see
and its gcf because inside () has no common factors
Answer:
La respuesta es falso.
Step-by-step explanation:
La respuesta es falso.
Cuando se suman fraccciones con igual denominador, se suman los numeradores (numerador con numerador) y se deja el mismo denominador (el cual es común en ambos). Por ejemplo, la suma de 1/5 + 3/5 da como resultado:
En el caso de fracciones con diferentes denominadores, tampoco se suma numerador con numerador y denominador con denominador. En ese caso se debe encontrar el mínimo común múltiplo.
Por lo tanto, la respuesta es falso.
Espero que te sea de utilidad!
13,822 to one significant figure is 10,000
623 to one significant figure is 600
14 to one significant figure is 10
10,000 times 600 = 6,000,000
6,000,000/10 = 600,000
This problem can be readily solved if we are familiar with the point-slope form of straight lines:
y-y0=m(x-x0) ...................................(1)
where
m=slope of line
(x0,y0) is a point through which the line passes.
We know that the line passes through A(3,-6), B(1,2)
All options have a slope of -4, so that should not be a problem. In fact, if we check the slope=(yb-ya)/(xb-xa), we do find that the slope m=-4.
So we can check which line passes through which point:
a. y+6=-4(x-3)
Rearrange to the form of equation (1) above,
y-(-6)=-4(x-3) means that line passes through A(3,-6) => ok
b. y-1=-4(x-2) means line passes through (2,1), which is neither A nor B
****** this equation is not the line passing through A & B *****
c. y=-4x+6 subtract 2 from both sides (to make the y-coordinate 2)
y-2 = -4x+4, rearrange
y-2 = -4(x-1)
which means that it passes through B(1,2), so ok
d. y-2=-4(x-1)
this is the same as the previous equation, so it passes through B(1,2),
this equation is ok.
Answer: the equation y-1=-4(x-2) does NOT pass through both A and B.
