Answer:
Step-by-step explanation:
5x=y+6 --------- equ 1
2x-3y=4 -------- equ 2
5x - 6 = y
y = 5x - 6
substitute in equ 2
2x-3(5x - 6) =4
2x - 3*5x + 3*6 = 4
2x - 15x + 18 = 4
- 13x = 4 - 18
-13x = -14
x = -14/-13
x = 14/13
substitute in equ 1
5*14/13 = y+6
70/13 - 6 = y
y = ( 70 - 78)/13
y = -8/13
OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
Box a should have 30 pieces of chocolate and box b should have 20 pieces of chocolate
